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nevsk [136]
3 years ago
7

Choose the correct translation of the following statement into symbolic form using the uppercase letters available. If neither w

ater nor soft drinks can quench your thirst, then juice will not do it, unless the juice contains electrolytes. Let W = water can quench your thirst, S = soft drinks can quench your thirst, J = juice will quench your thirst, and E= the juice contains electrolytes a)-(WvS)-(-VE) b) - (WvS) (-) El c)-(WvS) (-JVE) d) - (Wv 5)(-). E) Question 16 (1 point) Choose the correct translation of the following statement into symbolic form using the uppercase letters available. If the dryer breaks, then we will hang the clothes to dry, or take the clothes to a coin-operated laundry. Let D = the dryer breaks, B = we will hang the clothes to dry, and C = we will take the clothes to a coin-operated laundry a) (DB) b)(DVB) vc c) CV (DB) d) DBVC Question 17 (1 point) If " X is true, then what is X? a) X is true. b) Xis false. c) X could be true or false. Question 18 (1 point) If "Xv Y is false, then can one of the disjuncts be true? a) Yes O b) No
Mathematics
1 answer:
Over [174]3 years ago
5 0

Answer:

¬(W∨S)→¬(J∨E)

D→(B∨C)

X is true

No

Step-by-step explanation:

The hypotheses  "neither water nor soft drinks can quench your thirst" translates to ¬(W∨S) ("neither nor" negates the disjunction W∨S). The "if,... then" translates to the implication symbol (arrow). The conclusion "juice will not do it, unless the juice contains electrolytes" translates to ¬(J∨E). This is because if J or E were true, then J would be true (because E implies J), contrary to the conclusion that J is false ("juice will not do it"), then J∨S is false.

The hypothesis here is "the dyer breaks" hence D is the hypothesis. The conclusion is "we will hang the clothes to dry, or take the clothes to a coin-operated laundry" which is the same as (B∨C).

The proposition p→p is always true (according to truth tables). In this case, p:=X is true, then p is true and X is true.

X∨Y is false if and only if X is false and Y is false, so both statements X,Y must be false.

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A graph of a quadratic function is shown below.
stira [4]

Answer:

d. (10,800)

Step-by-step explanation:

Vertex appears to be at x = 10

Vertex: (10,800)

6 0
3 years ago
What is the domain of the function given below
MA_775_DIABLO [31]

Answer:

c. [-1, infinity)

Step-by-step explanation:

the domain the interval or set of valid x values (while the range is the same for the valid y values).

what is the smallest value of x we see for the graph ?

for x values we need to look left and right.

and the more left the value, the smaller it is.

so, in other words, what is the left-most x value e can find ?

x = -1

that is the "starting point" of the function. there is no functional value for any smaller x.

and then clearly, the function goes on and on to the right without any boundary in sight. so, it keeps going to the right in all eternity, that means it goes to infinity.

therefore the answer.

keep in mind that "infinity" is not a number, only a concept. so, when writing "infinity" at an interval end, it is not included (and we use a round bracket).

8 0
2 years ago
Can somebody help me on this plz
rodikova [14]
The value will be  A= 87
6 0
2 years ago
Read 2 more answers
Please help!
FrozenT [24]
Points are collinear if they lie on the same line.

First find the equation of the line that passes through the points B and C.
B(4, -3) \\
x_1=4 \\ y_1=-3 \\ \\
C(-4,3) \\
x_2=-4 \\ y_2=3 \\ \\
m=\frac{y_2-y_1}{x_2-x_1}=\frac{3-(-3)}{-4-4}=\frac{3+3}{-8}=\frac{6}{-8}=-\frac{3}{4} \\ \\
y=-\frac{3}{4}x+b \\
(-4,3) \\
3=-\frac{3}{4} \times (-4)+b \\
3=3+b \\
b=0 \\ \\
y=-\frac{3}{4}x

The points lie on the line y=(-3/4)x.
Now plug the coordinates of the given points into the equation and check if they satisfy the equation.

(0,0) \\
x=0 \\ y=0 \\ \Downarrow \\
0 \stackrel{?}{=} -\frac{3}{4} \times 0 \\
0 \stackrel{?}{=} 0 \\
0=0 \\
\hbox{the point lies on the line} \\ \\
(1,1) \\
x=1 \\ y=1 \\ \Downarrow \\
1 \stackrel{?}{=} -\frac{3}{4} \times 1 \\
1 \stackrel{?}{=} -\frac{3}{4} \\
1 \not= -\frac{3}{4} \\
\hbox{the point doesn't lie on the line}


(1,-5) \\
x=1 \\ y=-5 \\ \Downarrow \\ -5 \stackrel{?}{=} -\frac{3}{4} \times 1 \\
-5 \stackrel{?}{=} -\frac{3}{4} \\
-5 \not= -\frac{3}{4} \\
\hbox{the point doesn't lie on the line} \\ \\
(6,-8) \\
x=6 \\ y=-8 \\ \Downarrow \\
-8 \stackrel{?}{=} -\frac{3}{4} \times 6 \\
-8 \stackrel{?}{=} -\frac{9}{2} \\
-8 \not= -\frac{9}{2} \\
\hbox{the point doesn't lie on the line}

The answer is A.
7 0
3 years ago
Read 2 more answers
Let u=(5,12) and c=-3. what is ||cu||
DedPeter [7]
||cu|| = |c| * |u| = c[ magnitude of vector sum of 5i + 12j ] = 3sqrt(5^2 + 12^2)

= 3sqrt(169) = 3(13) = 39 (answer) 
3 0
3 years ago
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