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Alborosie
3 years ago
14

What is a quartic function with only the two real zeroes given? x=5 and x=1

Mathematics
2 answers:
JulijaS [17]3 years ago
8 0

Answer: 1. B) -6, -2

2. A) 7 - square root 3, 2 + square root 6

3. B) 1, 3/2, +- 5i

4. D) s^5 + 40s^4v + 640s^3v^2 + 5,120s^2v^3 + 20,480sv^4 + 32,768v^5

5. B) y= x^3 + 4x -2x - 5

6. C) 7.5

7. A) 1

8. D) y=x^4-6x^3+6x^2-6x+5

Step-by-step explanation: 100% :)

Paha777 [63]3 years ago
7 0

The answer is

Y=x^4-6x^3 +6x^2 -6x+5

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The coordinates of PQR are P(1, 1), Q(2, 2), and R(3, 1). If PQR is rotated 90° about the origin, what are the vertices of P'Q'R
Valentin [98]

Answer:

(-1, 1), (-2, 2), and (-1, 3)

Step-by-step explanation:

The formula for rotation of a point (x,y) by an angle θ about the origin is  

x' = xcosθ  -  ysinθ

y' = ycosθ + xsinθ

If θ = 90°, sinθ = 1 and cosθ = 0, and the formula becomes

x' = -y

y' =  x

P: (1, 1)   ⟶ (-1,  1)

Q:(2, 2) ⟶ (-2, 2)

R: (3, 1) ⟶  (-1,  3)  

The vertices of P'Q'R' are (-1, 1), (-2, 2), and (-1, 3).

The Figure below shows the triangle before and after the rotation.

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4 years ago
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inysia [295]

x = \frac{k+c}{5}

isolate 5x by adding c to both sides of the equation

5x = k + c ( divide both sides by 5 )

x = \frac{k+c}{5}


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