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Ilia_Sergeevich [38]
2 years ago
11

Find the unknown angle measure by solving for the given variable.

Mathematics
1 answer:
pochemuha2 years ago
8 0

Answer:

10 1/2

Step-by-step explanation:

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Put a random answer or a correct answer. If you put. A correct answer put “correct” next to it if you put a random answer put “r
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Answer:

25in (correct)

3 0
2 years ago
Please help me answer this.
inna [77]

Answer:

D. 4,-1

Step-by-step explanation:

The mathmatical way to solev it is to find the linear equation and plug in the points, but i just looked at the graph to see which point was in the shaded region.

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3 years ago
Find x (geometry) plz help
Ilya [14]

Step-by-step explanation:

\frac{ \sin(x) }{12}  =  \frac{ \sin(75) }{22}  \\  \sin(x)  =  \frac{12 \sin(75) }{22}   \\  \sin(x)  = 0.5268 \\ x = 31.79 = 31.8

6 0
2 years ago
List all possible rational roots. Then use synthetic division to confirm which rational roots exist:
Kisachek [45]

Answer:

\boxed{(1) \, x = \, \pm \dfrac{1}{2}, \pm 1, \pm2, \pm \dfrac{5}{2}, \pm 5, \pm 10; (2) \, x = -2}

Step-by-step explanation:

2x³+ 6x² - x - 10 = 0

(1) Possible roots

The Rational Roots Theorem states that, if a polynomial has any rational roots, they will have the form p/q, where p is a factor of the constant term  and q is a factor of the leading coefficient.

\text{Possible rational root} = \dfrac{ p }{ q } = \dfrac{\text{factor of constant term}}{\text{factor of leading coefficient}}

In your function, the constant term is -10 and the leading coefficient is 2, so

\text{Possible root} = \dfrac{\text{factor of 10}}{\text{factor of 2}}

Factors of 10 = ±1, ±2, ±5, ±10

Factors of 2 = ±1, ±2

\text{Possible roots are } \large \boxed{\mathbf{x = \pm \dfrac{1}{2}, \pm 1, \pm2, \pm \dfrac{5}{2}, \pm 5, \pm 10}}

(2) Synthetic division

Rather than work through all 12 possibilities, I will do one that works.

\begin{array}{r|rrrr}-2 & 2 & 6 & -1 & -10\\& & -4& -4 & 10\\& 2 & 2& -5 & 0\\\end{array}

So, x = -2 is a root, and the quotient is 2x² + 2x - 5.

(3) Check for other rational roots

2x² + 2x - 5 = 0

D = b² - 4ac =2²- 4(2)(-5) = 4 + 40 = 44

√44 = 2√11, which is irrational.

Since irrational roots come in pairs, the cubic equation has two real, irrational roots and one rational root at x = -2.

6 0
3 years ago
Can someone plz help me I’m being timed hurry!!!!!!!!!!!!
rosijanka [135]

Answer:

...

Step-by-step explanation:

14, 18, 20

6 0
3 years ago
Read 2 more answers
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