F(x) 3x^2+x-3 g(x)=x^2-5x+1 find f(x)-g(x)

Mathematics

2 answers:

wel3 years ago

5 0

Answer:

2x² + 6x - 4

Step-by-step explanation:

f(x) - g(x)

= 3x² + x - 3 - (x² - 5x + 1) ← distribute

= 3x² + x - 3 - x² + 5x - 1 ← collect like terms

= 2x² + 6x - 4

TEA [102]3 years ago

5 0

Answer:

f(x) - g(x) = 2x² - 4x - 2

Step-by-step explanation:

f(x) = 3x² + x - 3

g(x) = x² - 5x + 1

f(x) - g(x)

3x² + x - 3 - x² - 5x + 1

3x² - x² - 5x + x - 3 + 1

= 2x² - 4x - 2

f(x) - g(x) = 2x² - 4x - 2

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This is a pre calculus question that I need help with, serious answer PLEASE and thank you! Will give brainliest.

IRISSAK [1]

The wording of this question is a bit confusing... You can't write a sequence in sigma notation, but rather a series or sum. I think the question is asking you to write the sum of the sequence,

$\dfrac12,\dfrac14,\dfrac18,\ldots,\dfrac1{64}$

which would be

$\dfrac12+\dfrac14+\dfrac18+\cdots+\dfrac1{64}$

in sigma notation.

To do this, notice that the denominator in each term is a power of 2, starting with $2^1=2$ and ending with $2^6=64$ . So in sigma notation, this series is