Which graph best represents the solution set of y+4>2x

Find the surface area of a right square pyramid if the area of the base is 3636 cm squaredcm2 and the height of the pyramid is 6

Bond [772]

The surface area is 1203cm good luck on your homeworek

5 0

3 years ago

Read 2 more answers

A 1313-foot piece of string is cut into two pieces so that the longer piece is 44 feetfeet longer than twice the shorter piece.

Kitty [74]

Answer:

423

Step-by-step explanation:

Start by setting up a formula.

x = the shorter piece

total = 1313

longer piece = (x*2) + 44

x + (x*2) + 44 = 1313

Simplify

3x + 44 = 1313

Now we must solve for x.

Whatever you do on the left side of the equal sign must also be done on the right.

The goal is to get x by itself on the left side.

Do the easiest thing first, which is usually addition or subtraction. In this case, subtract 44 from both sides.

3x + 44 - 44 = 1313 - 44

3x = 1269

Now the only way to cancel out the 3 on the left is to divide by 3. Since 3/3 =1. Remember this must be done on both sides to keep things equal.

3x/3 = 1269/3

x=423

The End

8 0

4 years ago

I need help. I'm failing math

Alexxandr [17]

Answer:

B i believe

Step-by-step explanation:

6 0

3 years ago

In the expression 5x6 + 3xy − 7yz2 + , which of the following choices is the exponent in the term 5x6?

Bond [772]

Answer:

The exponent is 6.

Basically, the term 5x^6 is asking you to raise 'x' to the 6th power (the exponent) and then multiply it by 5.

Step-by-step explanation:

4 0

3 years ago

The Center for Medicare and Medical Services reported that there were 295,000 appeals for hospitalization and other Part A Medic

Ymorist [56]

Answer:

(a) 0.00605

(b) 0.0403

(c) 0.9536

(d) 0.98809

Step-by-step explanation:

We are given that 40% of first-round appeals were successful (The Wall Street Journal, October 22, 2012) and suppose ten first-round appeals have just been received by a Medicare appeals office.

This situation can be represented through Binomial distribution as;

$P(X=r)= \binom{n}{r}p^{r}(1-p)^{n-r} ; x = 0,1,2,3,....$

where, n = number of trials (samples) taken = 10

r = number of success

p = probability of success which in our question is % of first-round

appeals that were successful, i.e.; 40%

So, here X ~ $Binom(n=10,p=0.40)$

(a) Probability that none of the appeals will be successful = P(X = 0)

P(X = 0) = $\binom{10}{0}0.40^{0}(1-0.40)^{10-0}$

= $1*0.6^{10}$ = 0.00605

(b) Probability that exactly one of the appeals will be successful = P(X = 1)

P(X = 1) = $\binom{10}{1}0.40^{1}(1-0.40)^{10-1}$

= $10*0.4^{1} *0.6^{10-1}$ = 0.0403

(c) Probability that at least two of the appeals will be successful = P(X>=2)

P(X >= 2) = 1 - P(X = 0) - P(X = 1)

= 1 - $\binom{10}{0}0.40^{0}(1-0.40)^{10-0} - \binom{10}{1}0.40^{1}(1-0.40)^{10-1}$

= 1 - 0.00605 - 0.0403 = 0.9536

(d) Probability that more than half of the appeals will be successful = P(X > 0.5)

For this probability we will convert our distribution into normal such that;

X ~ N( $\mu = n*p=4,\sigma^{2}= n*p*q = 2.4$ )

and standard normal z has distribution as;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

P(X > 0.5) = P( $\frac{X-\mu}{\sigma}$ > $\frac{0.5-4}{\sqrt{2.4} }$ ) = P(Z > -2.26) = P(Z < 2.26) = 0.98809

3 0

3 years ago