Given :
Challenge given is to volunteer for about 1 1/2 hours per week .
Autum did at a rate of 6 3/4 hours per week .
To Find :
The comparison ( ratio ) her volunteers rate with the challenge rate .
Solution :
Simplifying challenge rate in in normal fraction , .
Also , simplifying her rate , .
Now , ratio of his work by challenge is :
Therefore , the ratio is 9/2 or 4 1/2 .
Hence , this is the required solution .
the sine function is a many-to-one function and therefore has no inverse function.
However if the domain is restricted to -90° ≤ x ≤ 90°
Then the function is one-to-one for this domain
Thus, x is defined as the angle such that - π/2 ≤ x ≤ π/2
5π/6 is therefore outwith the domain
Answer:
Critical value is -1.98.
Step-by-step explanation:
Given:
The value of alpha is,
Now, in order to find the critical value, we need to subtract alpha from 1 and then look at the z-score table to find the respective 'z' value for the above result.
The probability of critical value is given as:
So, from the z-score table, the value of z-score for probability 0.976 is 1.98.
Now, in a left tailed test, we multiply the z value by negative 1 to arrive at the final answer. We do so because the area to the left of mean in a normal distribution curve is negative.
So, the z-score for critical value 0.024 in a left tailed test is -1.98.