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3 years ago

Lin solved the equation

Mathematics

1 answer:

Alekssandra [29.7K]3 years ago

3 0

Answer: x=1/2

she was wrong, it's supposed to be

Step-by-step explanation: 8(x−3)+7=2x(4−17)

Step 1: Simplify both sides of the equation.

8(x−3)+7=2x(4−17)

(8)(x)+(8)(−3)+7=2x(4−17)(Distribute)

8x+−24+7=−26x

(8x)+(−24+7)=−26x(Combine Like Terms)

8x+−17=−26x

8x−17=−26x

Step 2: Add 26x to both sides.

8x−17+26x=−26x+26x

34x−17=0

Step 3: Add 17 to both sides.

34x−17+17=0+17

34x=17

Step 4: Divide both sides by 34.

34x/34=17/34 x=1/2

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A number greater than 1000 whose prime factorization contains 1 prime number that does not repeat,1 prime number that repeats 3

olasank [31]

Heheheyyeyyehehhwjjwjwjjwhwhhw

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4 years ago

A rectangular auditorium seats 1344 people. The number of seats in each rows exceeds the number of rows by 20. Find the number o

Tasya [4]

Let the number of rows be x

rows = x
seats in each row = x + 20

total seats = 1344
x (x + 20) = 1344
x^2 + 20x - 1344 = 0
(x + 48)(x - 28) = 0
x = -48 (rejected, answer cannot be negative) or x = 28

Therefore,
x = 28
x + 20 = 48

Check:
Row = 28
Numbers of seat per row = 28 + 20 = 48
28 x 48 = 1344 (Correct)

Ans:There are 48 seats per row

8 0

4 years ago

10. Simplify the following expression: 35 + (–13) + (+8) – (–6).

nadezda [96]

$35 + (-13) + (+8) - (-6)\\35-13+8+6\\22+14\\36$

B. 36

8 0

3 years ago

Read 2 more answers

There is a 60% chance of rain on Saturday and a 20% chance of rain on Sunday. Assume that the event that it rains on Saturday is

Vsevolod [243]

Answer:

$0.56$

Step-by-step explanation:

GIVEN: There is a $60\%$ chance of rain on Saturday and a $20\%$ chance of rain on Sunday. Assume that the event that it rains on Saturday is independent of the event that it rains on Sunday.

TO FIND: What is the probability that it rains on exactly one day over the weekend.

SOLUTION:

Probability of rain on Saturday $P(A)=0.6$

Probability of not raining on Saturday $P(A^{'}) =1-0.6=0.4$

Probability of rain on Sunday $P(B)=0.2$

Probability of not raining on Saturday $P(B^{'})=1-0.2=0.8$

Probability of raining exactly one day over the weekend

$=\text{Probability it rains only on Saturday}+\text{Probability it rains only on Sunday}$

$=P(A)\times P(B^{'})+P(B)\times P(A^{'})$

$=0.6\times0.8+0.2\times0.4$

$=0.56$

Hence probability of raining exactly only one day over the weekend is $0.56$

5 0

4 years ago

Do any of you get this question? Please help!

Alexxandr [17]

Honestly i just wanted to try this question since ive never seen it but i dont rlly know if i did it right at all

I equaled GH, HI, and GI together to get y

which i got y=-2

and what i got next i feel is off since

GH, HI, and GI all equaled -11

if you kind of know how to do the question maube you could correct me from there but otherwise dont take my word for it completely

4 0

3 years ago