<u>Answer:</u>
plz mark me as brainliest ...TOOK ME LONG TIME TO TYPE
answer = CI = 3108 RUPEES
<u>Step-by-step explanation:</u>
i am doing the method in which u find the simple interest of first year then second year.
SI FOR 1ST YEAR= P X R X T / 100
SI = 2700 X 20 X 2 / 3 X 100 ( RATE OF INTEREST IS 20 / 3)
SI = 108000/300
SI = 360
SI FOR SECOND YEAR =
P = 2700 + 360= 3060
SI = 3060 X 20 X 2 / 300
SI= 122400 / 300
SI = 408
COMPOUND INTEREST (CI) = PRINCIPLE + SI OF 2ND YEAR
CI = 2700 + 408
CI = 3108 RUPEES
or u can solve be the method
CI = amount - principle
Amount= principle x (change in ratio) raised to time
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I have no idea what that is but good luck
Answer:
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Step-by-step explanation:
(I typed with a keyboard)
Answer:
0.918 is the probability that the sample average sediment density is at most 3.00
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 2.80
Standard Deviation, σ = 0.85
Sample size,n = 35
We are given that the distribution of sediment density is a bell shaped distribution that is a normal distribution.
Formula:
Standard error due to sampling:
P(sample average sediment density is at most 3.00)
Calculation the value from standard normal z table, we have,
0.918 is the probability that the sample average sediment density is at most 3.00
Answer: B = 9
Step-by-step explanation:
16-b=7
Rearrange so we can subtract 16 by 7
16 - 7 = 9
Substituting 9 for b and making sure it's correct.
16 - 9 = 7
