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gizmo_the_mogwai [7]

3 years ago

5

OMG I NEEP HELP I DONT KNOW WHAT 2+2 IS HELP ME PLSSSSSS

2 answers:

mixas84 [53]3 years ago

5 0

Answer:

omgg i dont knowww

lets see if we take the square root of two then multiply it by five: its roughly 7.071

then after that we take the extra 0.071 and throw it in the trash

we next take 1+1+1 and subtract it from the extra seven we have left over

we end up with four.

maybe of course, this is an approximation

Mekhanik [1.2K]3 years ago

3 0

Answer:

4 UNLESS IM WRONG MAYBE ITS 21

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Princess Poly claims that the equation (3x−4i)(7x−8)(3x+4i)=0 has three roots, a real root and a complex root with a multiplicit

Serjik [45]

Given equation:

$(3x-4i)(7x-8)(3x+4i)=0$

i.e., $3x-4i=0$ and $7x-8=0$ and $3x+4i=0$

i.e., $3x=4i$ and $7x=8$ and $3x=-4i$

i.e., $x=\frac{4i}{3}$ and $x=\frac{8}{7}$ and $x=-\frac{4i}{3}$

Therefore, the given equation has a real root i.e., $x=\frac{8}{7}$

and two complex conjugate roots i.e., $x=\frac{4i}{3}$ and $x=-\frac{4i}{3}$

Hence, option C is correct.

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3 years ago

The coordinates of the vertices of △JKL are J(1, 4) , K(6, 4) , and L(1, 1) .

gayaneshka [121]

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3 years ago

Read 2 more answers

Jorge has some dimes and quarters. He has 10 more dimes than quarters and the collection of coins is worth $2.40. How many dimes

PIT_PIT [208]

Answer:

14 dimes and 4 quarters

Step-by-step explanation:

x= number of dimes

y=number of quarters

x-10=y

0.10x+0.25y=2.40

substitute for y

0.10x+0.25(x-10)=2.40

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3 years ago

A lampshade has a height of 12cm and upper and lower diameters of 10cm and 20cm A)what area of material is required to cover tha

netineya [11]

Answer:

$(a)\ Area = 195\pi$

$(b)\ Volume = 700\pi$

Step-by-step explanation:

Given

$h = 12$

$d_1 = 10$ --- lower diameter

$d_2 = 20$ --- upper diameter

Solving (a): The curved surface area

This is calculated as:

$Area = \pi l(r_1 + r_2)$

Where

$r_1 = 0.5 * d_1 = 0.5 * 10 = 5$ --- lower radius

$r_2 = 0.5 * d_2 = 0.5 * 20 = 10$ --- upper radius

And

$l = \sqrt{h^2 + (r_1 - r_2)^2$ ---- l represents the slant height of the frustrum

$l = \sqrt{12^2 + (5 - 10)^2$

$l = \sqrt{12^2 + (-5)^2$

$l = \sqrt{144 + 25$

$l = \sqrt{169$

$l = 13$

So, we have:

$Area = \pi l(r_1 + r_2)$

$Area = \pi * 13(5 + 10)$

$Area = \pi * 13(15)$

$Area = 195\pi$

Solving (b): The volume

This is calculated as:

$Volume = \frac{1}{3}\pi * h * (r_1^2 + r_2^2 + (r_1 * r_2))$

This gives:

$Volume = \frac{1}{3}\pi * 12 * (5^2 + 10^2 + (5 * 10))$

$Volume = \frac{1}{3}\pi * 12 * (25 + 100 + (50))$

$Volume = \frac{1}{3}\pi * 12 * (175)$

$Volume = \pi *4 * 175$

$Volume = 700\pi$

6 0

3 years ago

Write the standard equation of the circle shown.

zysi [14]

Answer:

b

Step-by-step explanation:

The equation of a circle centred at the origin is

x² + y² = r² ← r is the radius

The circle shown is centred at the origin and has a radius of 5, thus

x² + y² = 5² ⇒ x² + y² = 25 → b

4 0

3 years ago