9514 1404 393
Answer:
(9/34)√34 ≈ 1.543
Step-by-step explanation:
The second equation can be rewritten as ...
6x -10y -12 = 0
3x -5y -6 = 0
3x -5y = 6
__
The formula for the distance from point (x, y) to line ax+by+c=0 is ...
d = |ax+by+c|/√(a²+b²)
Then the distance from a point to the first line is ...
d = |3x -5y +3|/√(3² +(-5)²)
We know from the rearrangement of the second equation that points on its line satisfy (3x-5y) = 6. Substituting this value for (3x -5y) in the distance formula gives ...
d = |6 +3|/√34
Simplifying and rationalizing the denominator gives a distance of ...
d = (9/34)√34 ≈ 1.543
Answer:
They both are the same thing. Rate of change is change in y over change in x which is what slope is on a graph.
Answer:
- domain: -∞ < x < ∞
- range: -2 ≤ y < ∞
Step-by-step explanation:
<u>Domain</u>
The domain is the horizontal extent of the function, the set of input values for which it is defined. A parabola that opens up or down is defined for all x values, so its domain is ...
-∞ < x < ∞ . . . . . . (-∞, ∞) in interval notation
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<u>Range</u>
The range is the vertical extent of the function, the set of output values it produces. The vertex of the parabola is one extreme of the range. Depending on the direction it opens, the other extreme will be +∞ or -∞. The range includes the y-value of the vertex. Here, the range is ...
-2 ≤ y < ∞ . . . . . . [-2, ∞) in interval notation
Our function f(x) can be rewritten if we factor out a common x^2 from each term:

Now inside the parentheses we have a polynomial of the form a^2 - b^2, or the difference of two perfect squares, which can be factored as (a+b)(a-b) so we have:

Setting our function equal to zero gives us the roots x = 0, x = 4, and x = -4.
The multiplicity of the root zero is two since it occurs twice, and the others are one since they occur only once. If you graph the function you can see that it will only touch the x-axis at x = 0, but will cross the x-axis at x = 4 and x = -4.
Time taken for the amount deposited to grow to $5000 will be found as follows:
A=P(1+r/100*n)^nt
where:
A=amount
P=principle
r=rate
n=number of terms
t=time
thus plugging in our values we have:
5000=3587.39=(1+4.2/200)^2t
solving for t we have:
1.393771=1.021^2t
2t=ln1.393771/ln1.021
2t=16.111
t=8.055685 years~8 years