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2 years ago

7

How are circumference and area the same? How are they different?

1 answer:

Sindrei [870]2 years ago

3 0

In geometry, the circumference (from Latin circumferences, meaning "carrying around") of a circle is the (linear) distance around it. That is, the circumference would be the length of the circle The area of a circle is pi (approximately 3.14) times the radius of the circle squared.

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Sarah is buying some school clothes.

Svetllana [295]

The answer is the first one

6 0

2 years ago

a baseball team played 154 games last season the had 35 fewer losses than wins how many games did the team win and how many did

dsp73

do 154 / 2 and then add 35 and that is how much they won. do 154 / 2 and then subtract 35 and that is how much they loss

8 0

2 years ago

Can yall help me please

Luda [366]

√896z^15/<span>√225z^6

= </span>√896z^9/<span>√225

= </span>√64√14(z^4)<span>√z/15

= 8</span>√14(z^4)<span>√z/15

= (8z^4/15) * </span><span>√14z

x = 8</span>

7 0

2 years ago

given that sin theta= 1/4, 0 is less than theta but less than pi/2, what is the exact value of cos theta

lapo4ka [179]

Answer:

$\cos{\theta} = \frac{\sqrt{15}}{4}$

Step-by-step explanation:

For any angle $\theta$ , we have that:

$(\sin{\theta})^{2} + (\cos{\theta})^{2} = 1$

Quadrant:

$0 \leq \theta \leq \frac{\pi}{2}$ means that $\theta$ is in the first quadrant. This means that both the sine and the cosine have positive values.

Find the cosine:

$(\sin{\theta})^{2} + (\cos{\theta})^{2} = 1$

$(\frac{1}{4})^{2} + (\cos{\theta})^{2} = 1$

$\frac{1}{16} + (\cos{\theta})^{2} = 1$

$(\cos{\theta})^{2} = 1 - \frac{1}{16}$

$(\cos{\theta})^{2} = \frac{16-1}{16}$

$(\cos{\theta})^{2} = \frac{15}{16}$

$\cos{\theta} = \pm \sqrt{\frac{15}{16}}$

Since the angle is in the first quadrant, the cosine is positive.

$\cos{\theta} = \frac{\sqrt{15}}{4}$

3 0

2 years ago

Solve for w.<br> 40+4w=12w

Xelga [282]

Answer:

W=5

Step-by-step explanation:

40+4w=12w

-4w -4w

40= 8w

÷8 ÷8

5=w

7 0

2 years ago