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Lelu [443]
4 years ago
11

three students gambled with the amount of 7:6:5 and finished with sums in the ratio 1:4:7 . if one of them lost $22, then what w

ould the total amount at the start of the game be?
Mathematics
1 answer:
agasfer [191]4 years ago
8 0
Make the ratios have a common "total."

7:6:5 is the start
change 1:4:7 to 1.5:6:10.5 so that there are 18 parts.

the only person who lost, lost 5.5 parts which is $22

each part is $4

there are 18 parts, they started out with $72
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3 years ago
Read 2 more answers
A ball is tossed between three friends. The first toss is 8.6 feet, the second is 5.8 feet, and the third toss is 7.5 feet, whic
algol13

Answer:

The angles are 79.45, 59.02 and 41.53 degrees to the nearest hundredth.

Step-by-step explanation:

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Using the Cosine Rule to find the measure of the angle opposite the side of length 8.6 feet:

cos X =  (8.6^2 - 5.8^2 - 7.5^2) / ( -2*5.8*7.5)

=  0.18310

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We can now find another angle using the sine rule:

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3 0
4 years ago
20)
Nataly [62]

Answer:

babysitting = $9

working at coffeehouse = $12

x = hours for babysitting

y = hours at coffeehouse

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iv) use <

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7 0
3 years ago
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