Answer:
1=1 times 2/2 1 + 2=2 times 3/2 1 +2+3=3 times 4/2 1+2+3+4=4 times 5/2 1+2+3+4+5=5 times 6/2
capital A
lower case and upper case v
lower case and upper case o
lower case and upper case i
lower and upper case w
Answer:for ax^2+bx+c=0 the discriminant is b^2-4ac
there are 3 basic cases of what happens for different discriminants
1. if the discriminant is less than 0, then there are no real zeroes
2. if the discriminant is 0, then it has 1 zero
3. if the discriminant is greater than 0, it has 2 zeroes
so given
0=3x^2-7x+4
a=3,b=-7,c=4
thus the discriminant is (-7)^2-4(3)(4)=49-48=1
the discriminant is 1. 1 is positive, thus the equation has 2 zeroes because the discriminant is greater than 0
the answer is the equation has two zeroes because the discriminant is greater than 0
Step-by-step explanation:
Answer:
rounded to the nearest 10: 680
rounded to the nearest 100: 700
Step-by-step explanation:
9 rounds up to 10 so it would go to 80
and 6 rounds up to 10 also so it goes to 700
brainilest maybe?
It might be 9 if it's not 6 ...but I can't see how it wouldn't be 6?
