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2 years ago

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An engineer wrote down the following estimates in his log book: 120, 130, 150, 180, 190 The median of this data set is 150. If t

wo numbers less that 120 were added to the data set, how would that affect the median? *

1 answer:

ANEK [815]2 years ago

6 0

Answer: The median would be 130.

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What is the general form of the equation of the line shown?

Nostrana [21]

Hey There!

The formula of the general form equation is

0 = Ax + By + C

As we look at the answer choices we see that the last choice best represents the correct answer.

x + y + 2 = 0

Best matches the formula given and therefore that would be the correct answer.

Thus, the answer would be x + y + 2 = 0

Thank you for posting your question with Brainly!

5 0

2 years ago

Read 2 more answers

a bag contains eleven counters. five are white. a counter is taken out the bag and is not replaced. a second counter is taken ou

Fed [463]

Answer:

$\displaystyle P(A)=\frac{6}{11}$

Step-by-step explanation:

<u>Probabilities</u>

The question describes an event where two counters are taken out of a bag that originally contains 11 counters, 5 of which are white.

Let's call W to the event of picking a white counter in any of the two extractions, and N when the counter is not white. The sample space of the random experience is

$\Omega=\{WW,WN,NW,NN\}$

We are required to compute the probability that only one of the counters is white. It means that the favorable options are

$A=\{WN,NW\}$

Let's calculate both probabilities separately. At first, there are 11 counters, and 5 of them are white. Thus the probability of picking a white counter is

$\displaystyle \frac{5}{11}$

Once a white counter is out, there are only 4 of them and 10 counters in total. The probability to pick a non-white counter is now

$\displaystyle \frac{6}{10}$

Thus the option WN has the probability

$\displaystyle P(WN)=\frac{5}{11}\cdot \frac{6}{10}=\frac{30}{110}=\frac{3}{11}$

Now for the second option NW. The initial probability to pick a non-white counter is

$\displaystyle \frac{6}{11}$

The probability to pick a white counter is

$\displaystyle \frac{5}{10}$

Thus the option NW has the probability

$\displaystyle P(NW)=\frac{6}{11}\cdot \frac{5}{10}=\frac{30}{110}=\frac{3}{11}$

The total probability of event A is the sum of both

$\displaystyle P(A)=\frac{3}{11}+\frac{3}{11}=\frac{6}{11}$

$\boxed{\displaystyle P(A)=\frac{6}{11}}$

7 0

2 years ago

The company charges $5 per sq ft, AND has a minimum charge of 3 sq ft per order (meaning if a customer orders something SMALLER

Sindrei [870]

Answer:

15 dollars

Step-by-step explanation:

12 inches = 1 ft

so 12 inch by 12 inches is 1 ft * 1 ft

1 ft* 1 ft

1 ft^2

This is smaller than 3 ft^2 so they will get charged for 3 ft^2

3 ft^2 = 3 ft^2 * $5 / ft^2 = 15 dollars

6 0

2 years ago

Select the expressions that are equivalent to 12n - 8. Select all that apply.

morpeh [17]

A.3n+4+3n+4+4n

=3n+3n+4n+4+4

=10n+8

B.11n+4+n-12

=11n+n+4-12

=12n-8

C.6(6n-2)

=36n-12

D.4(3n-2)

=12n-8

E.4n+22-12+8n

=4n+8n+22-12

=12n+10

so,B and D are the expressions that are equivalent to 12n-8.

3 0

1 year ago

If I have 150,000 crystals, and ONE costume cost 4,000 crystals, how many costumes can I buy total?

MArishka [77]

Okay, think of it this way:

You have to find how many times 4,000 goes into 150,000.

This will tell you how many costumes you can buy.

To make this easier, we can divide 4 by 150. (this is proportional to 4,000 and 150,000 since we took 3 zeros from each number; you will get the same answer)

150/4= 37.5

You can buy 37 whole costumes.

Hope this helped!

6 0

2 years ago