3 years ago

If the zeros of a relation are x = Ź and x = 1 , determine the min/max value.

Mathematics

1 answer:

wel3 years ago

3 0

Answer:

Step-by-step explanation:

im big brain B)

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X/5 -8=4 find the value of x

elena-s [515]

Answer:

x=60

Step-by-step explanation:

I'm assuming you meant this: (x/5)-8=4

In which case you would add 8 to both sides to get rid of the 8 on the left (your goal is to get x by itself so you want to move the numbers on the x side to the other side of the equal sign)

(x/5)=12

Then you would multiply 5 on both sides to get rid of the fraction with the 5 on the bottom on the left side.

x=60

There's your answer.

6 0

3 years ago

Can someone help me with this

aleksandrvk [35]

Answer:

the answer to the second question is h^9

Step-by-step explanation:

you are subtracting 14-5=9

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3 years ago

У = 3х – 1<br>у = 3y= -13<br>

Elina [12.6K]

Answer:

y=1/3x-1/3

Step-by-step explanation:

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3 years ago

Find the value of x such that the data set has the given mean 98, 122, 106, 112, 106, x; mean 114

Licemer1 [7]

Answer:

140

Step-by-step explanation:

$Mean=\frac{sum of datas}{number of data's}\\\\\frac{98+122+106+112+106+x}{6}=114\\\\\frac{544+x}{6}=114\\\\544+x=114*6\\\\544+x=684\\\\x=684-544\\\\x=140\\$

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3 years ago

fourth,sixth and thirteenth term in this sequence A(n)= 6+(n+1)(-2) help me to find and describe the explicite formula

OleMash [197]

Hello,

A(n)=6+(n+1)^(-2)=6+1/(n+1)²

$A_{4} =6+ \dfrac{1}{(4+1)^2} =6+ \dfrac{1}{25}= \dfrac{151}{25} \\

 A_{6} =6+ \dfrac{1}{(6+1)^2} =6+ \dfrac{1}{49}= \dfrac{295}{49} \\

 A_{13} =6+ \dfrac{1}{(13+1)^2} =6+ \dfrac{1}{196}= \dfrac{1177}{196} \\
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7 0

4 years ago