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Reil [10]
3 years ago
11

Tameka uses a scale of 1 inch to 265 feet to draw a map of her favorite bike path. On Tameka's map, the bike path's length is 23

.25 inches.
What is the exact length of the actual bike path?
Enter your answer in the box.
_____ ft
Mathematics
2 answers:
Dafna1 [17]3 years ago
8 0
We can solve this by setting up a proportion:

1 in/265 ft=23.25 in/ x ft

We can solve for x by cross multiplying:

(1)(x)=(265)(23.25)
x=6161.25 ft
marta [7]3 years ago
4 0

Answer:

x=6161.25 ft..?

Step-by-step explanation:


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What are the slope and the y-intercept of the linear function that is represented by the table?
mafiozo [28]

Answer:

slope is -2 and the y-intercept is 12

Step-by-step explanation:

a key thing to remember: x is always equal to 0 when finding the y-intercept.

so if you look at the table for where 0 is, you get the point (0,12) meaning the y-intercept is 12.

to find the slope use the equation: slope= change in y/change in x

you can use any two points to find this.

lets take the points of the x-intercept (6,0) and the y-intercept (0,12)

12-0/0-6

12/-6

-2 = slope

8 0
3 years ago
Please help. I'll give brainliest :)
Amanda [17]

Answer:

it would be 100

Step-by-step explanation:

if 1=50 and you have 2 then multiple 50 by 2 and that gives you 100

8 0
3 years ago
Question 3
Katyanochek1 [597]

Answer:

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Step-by-step explanation:

5 0
3 years ago
If you need $8000 to travel to Europe after you graduate in 4 year. How much would your monthly deposits need to be if your acco
lina2011 [118]
\bf \qquad \qquad \textit{Future Value of an ordinary annuity}\\
\left. \qquad \qquad \right.(\textit{payments at the end of the period})
\\\\
A=pymnt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right]

\bf \qquad 
\begin{cases}
A=
\begin{array}{llll}
\textit{accumulated amount}\\
\end{array}\to &
\begin{array}{llll}
8000
\end{array}\\
pymnt=\textit{periodic payments}\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{monthly, thus twelve}
\end{array}\to &12\\
t=years\to &4
\end{cases}

\bf 8000=pymnt\left[ \cfrac{\left( 1+\frac{0.05}{12} \right)^{12\cdot 4}-1}{\frac{0.05}{12}} \right]
\\\\\\
\cfrac{8000}{\left[ \frac{\left( 1+\frac{0.05}{12} \right)^{12\cdot 4}-1}{\frac{0.05}{12}} \right]}=pymnt\implies \cfrac{8000}{\frac{\left( \frac{241}{240} \right)^{48}-1}{\frac{1}{240}}}=pymnt
\\\\\\
\cfrac{8000}{53.0148852}\approx pymnt\implies 150.9010152318\approx pymnt
6 0
3 years ago
Can someone help me?! I don’t understand how to do these problems
Dmitriy789 [7]

Answer:

first do 9x40 and get your answer then do 18x3 and get that answer and then add to do answers together

7 0
3 years ago
Read 2 more answers
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