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melomori [17]
3 years ago
14

A company’s board of directors took a random sample of 10% of the company’s employees and surveyed them about their happiness at

work. What would most likely happen if they decided to randomly sample 15% of the company’s employees instead?
A. The sample mean would more closely model the population mean.
B. The sample mean would not be affected.
C. There is not enough information to determine how the sample mean would be affected.
D. The sample mean would less closely model the population mean.
Mathematics
2 answers:
Bingel [31]3 years ago
7 0

Answer:

The sample mean would more closely model the population mean.

Step-by-step explanation:

melisa1 [442]3 years ago
6 0
D the sample mean would less closely model the population mean
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An insurance company selected a random sample of 500 clients under 18 years of age and found that 180 of them had had an acciden
Butoxors [25]

Answer:

a) The pooled proportion is p=0.3.

b) P-value = 0.000078

c) Lower bound = 0.0556

d) Upper bound = 0.1644

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that the accident proportions differ between the two age groups .

Then, the null and alternative hypothesis are:

H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2\neq 0

The significance level is 0.05.

The sample 1, of size n1=500 has a proportion of p1=0.36.

p_1=X_1/n_1=180/500=0.36

The sample 2, of size n2=600 has a proportion of p2=0.25.

p_1=X_1/n_1=150/600=0.25.

The difference between proportions is (p1-p2)=0.11.

p_d=p_1-p_2=0.36-0.25=0.11

The pooled proportion, needed to calculate the standard error, is:

p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{180+150}{500+600}=\dfrac{330}{1100}=0.3

The standard error for the difference between proportions can now be calculated as:

The estimated standard error of the difference between means is computed using the formula:

s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.3*0.7}{500}+\dfrac{0.3*0.7}{600}}\\\\\\s_{p1-p2}=\sqrt{0.00042+0.00035}=\sqrt{0.00077}=0.0277

Then, we can calculate the z-statistic as:

z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{0.11-0}{0.0277}=\dfrac{0.11}{0.0277}=3.964

This test is a two-tailed test, so the P-value for this test is calculated as (using a z-table):

P-value=2\cdot P(t>3.964)=0.000078

As the P-value (0.000078) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is  enough evidence to support the claim that the accident proportions differ between the two age groups.

If we want to calculate the bounds of a 95% confidence interval, we start by calculating the margin of error.

For a 95% CI, the critical value for z is z=1.96.

Then, the margin of error is:

MOE=z \cdot s_{p1-p2}=1.96\cdot 0.0277=0.0544

Then, the lower and upper bounds of the confidence interval are:

LL=(p_1-p_2)-z\cdot s_{p1-p2} = 0.11-0.0544=0.05561\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= 0.11+0.0544=0.16439

The  95% confidence interval for the population mean is (0.0556, 0.1644).

5 0
3 years ago
PLEASE ANSWER QUICK THIS IS TIMED AND I WILL GIVE BRAINLIEST I PROMISE! The amount of money in an account may increase due to ri
Mumz [18]

Answer:

This was timed and posted awile ago but I don't have the answer either way.

Step-by-step explanation:

5 0
3 years ago
Im bored lemme get yallz IG's please dont report :) oh happy saint patricks day :)
nikklg [1K]

Answer:7+7

Step-by-step explanation:

i didn't know it was st.patrick's day

4 0
3 years ago
12=10(s+4)+50 what is the written problem to this can you help me with the answer
muminat

Answer:

s = -7.8

Step-by-step explanation:

from the question 12=10(s+4)+50

<u>first step</u>

open the bracket and evaluate for the value of s

12=10(s+4)+50

12 = 10s + 40 + 50

12 = 10s + 90

collect or combine the like terms

12-90 = 10s

-78 = 10s

divide both side by 10

-78/10 = 10s/10

-7.8 = s

therefor s = -7.8

8 0
3 years ago
Complete the pairs of corresponding parts if ARSTE ATXY.
Mrac [35]
Answer is ztxy I think
8 0
3 years ago
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