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melomori [17]
3 years ago
14

A company’s board of directors took a random sample of 10% of the company’s employees and surveyed them about their happiness at

work. What would most likely happen if they decided to randomly sample 15% of the company’s employees instead?
A. The sample mean would more closely model the population mean.
B. The sample mean would not be affected.
C. There is not enough information to determine how the sample mean would be affected.
D. The sample mean would less closely model the population mean.
Mathematics
2 answers:
Bingel [31]3 years ago
7 0

Answer:

The sample mean would more closely model the population mean.

Step-by-step explanation:

melisa1 [442]3 years ago
6 0
D the sample mean would less closely model the population mean
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Sophia earned $294 in 24 hours. How many dollars did she earn per hour?
Vadim26 [7]

Answer:

$12.25

Step-by-step explanation:

Step 1:

$294 : 24        Ratio

Step 2:

$294 ÷ 24     Divide

Answer:

$12.25

Hope This Helps :)

6 0
3 years ago
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There are 37 more cats than dogs in an animal shelter. If there are 78 cats at he shelter, how many dogs are there?
Sloan [31]
There are 41 dogs in the shelter
8 0
3 years ago
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Will give brainliest D:
Monica [59]

<u>Answer</u>:

Given below.

<u>Step-by-step explanation</u>:

1) Hypotenuse

2) Using Pythagoras theorem:

              35² + 12² = c²

                c = √1225+144

                c = √1369

                 c = 37  ....this is the length of missing side.

Here given that opposite is 35 , adjacent is 12 , hypotenuse is 37.

3) sin(θ) = opposite/hypotenuse

   sin(θ) = 35/37

4) cos(θ) = adjacent/ hypotenuse

    cos(θ) = 12/37

5) tan(θ) = opposite/adjacent

      tan(θ) = 35/12

6 0
2 years ago
Read 2 more answers
Use long division to find the quotient. <br><br>(x²+6x-27) ÷ (x-3)
Alex
\frac{ x^2+6x-27 }{x-3} = \frac{ x^2+6x +3x-3x-27 }{x-3} = \frac{ x^2+9x-3x-27 }{x-3} = \\ \\ =\frac{ x(x +9 )-3(x+9) }{x-3} = \frac{ (x +9 ) (x-3) }{x-3} = x+9 \\ \\ \\ x-3\neq 0 \\x\neq 3\\D=R\setminus \left \{ 3 \right \}


4 0
3 years ago
Use spherical coordinates to find the volume of the region that lies outside the cone z = p x 2 + y 2 but inside the sphere x 2
Harman [31]

I assume the cone has equation z=\sqrt{x^2+y^2} (i.e. the upper half of the infinite cone given by z^2=x^2+y^2). Take

\begin{cases}x=\rho\cos\theta\sin\varphi\\y=\rho\sin\theta\sin\varphi\\z=\rho\cos\varphi\end{cases}\implies\mathrm dx\,\mathrm dy\,\mathrm dz=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi

The volume of the described region (call it R) is

\displaystyle\iiint_R\mathrm dx\,\mathrm dy\,\mathrm dz=\int_0^{2\pi}\int_0^{\sqrt2}\int_{\pi/4}^\pi\rho^2\sin\varphi\,\mathrm d\varphi\,\mathrm d\rho\,\mathrm d\theta

The limits on \theta and \rho should be obvious. The lower limit on \varphi is obtained by first determining the intersection of the cone and sphere lies in the cylinder x^2+y^2=1. The distance between the central axis of the cone and this intersection is 1. The sphere has radius \sqrt2. Then \varphi satisfies

\sin\varphi=\dfrac1{\sqrt2}\implies\varphi=\dfrac\pi4

(I've added a picture to better demonstrate this)

Computing the integral is trivial. We have

\displaystyle2\pi\left(\int_0^{\sqrt2}\rho^2\,\mathrm d\rho\right)\left(\int_{\pi/4}^\pi\sin\varphi\,\mathrm d\varphi\right)=\boxed{\frac43(1+\sqrt2)\pi}

4 0
3 years ago
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