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melomori [17]
2 years ago
14

A company’s board of directors took a random sample of 10% of the company’s employees and surveyed them about their happiness at

work. What would most likely happen if they decided to randomly sample 15% of the company’s employees instead?
A. The sample mean would more closely model the population mean.
B. The sample mean would not be affected.
C. There is not enough information to determine how the sample mean would be affected.
D. The sample mean would less closely model the population mean.
Mathematics
2 answers:
Bingel [31]2 years ago
7 0

Answer:

The sample mean would more closely model the population mean.

Step-by-step explanation:

melisa1 [442]2 years ago
6 0
D the sample mean would less closely model the population mean
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Step-by-step explanation:

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Each figure shows a pair of similar triangles, one contained in the other.
Alecsey [184]

Dilation involves enlarging or reducing the size of a shape.

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From the complete question, the side lengths of corresponding sides of both triangles are:

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This means that, the larger triangle is ABC, while the smaller triangle is AB'C'.

So, the scale factor of dilation from the larger triangle to the smaller triangle is:

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This gives

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Read more about dilation at:

brainly.com/question/3457976

7 0
2 years ago
A mean equal to 5 cm. A simple random sample of wrist breadths of 40 women has a mean of 5.07
neonofarm [45]

Answer:

The value of the test statistic is z = 1.34

Step-by-step explanation:

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

Test if the mean is equal to 5:

This means that the null hypothesis is \mu = 5

A simple random sample of wrist breadths of 40 women has a mean of 5.07 cm. The population standard deviation is 0.33 cm.

This means that n = 40, X = 5.07, \sigma = 0.33

Find the value of the test statistic?

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{5.07 - 5}{\frac{0.33}{\sqrt{40}}}

z = 1.34

The value of the test statistic is z = 1.34

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