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Anestetic [448]

2 years ago

15

Which equation could be used to solve the problem? Larry skated 7200 feet in 3 minutes. How many feet per minute did he skate (x

)? A. 7200 feet • 3 minutes = x B. 7200 feet + 3 minutes = x C. 7200 feet ÷ 3 minutes = x D. 3 minutes ÷ 7200 feet = x please help

1 answer:

kari74 [83]2 years ago

7 0

A. 7200 feet ÷ 3 minutes = x

Hope it helps!

And happy Pi Day! :D

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Greatest common factors<br><br> 4,8<br> Can u do a factor tree I need help with it

solong [7]

4. 8
/ \ / \
2 x 2. 4 x 2
/ \
2 x 2

4: 2x2
8: 2x2x2

The GCF is 4

7 0

3 years ago

Can someone pleas answer this

Dima020 [189]

83.7 m

18.6 / 3.6 = 5.166667

16.2*5.166667 = 83.7 m

7 0

2 years ago

What is the probability of getting a number greater than or equal to 5 when rolling a number cube numbered 1 to 6?

Dima020 [189]

Answer:

There is a 1/3 (or 0.33%) probability of rolling a number greater than or equal to 5.

Step-by-step explanation:

First, find what numbers are greater than or equal to 5:

5 and 6

Find what options you can get on a number cube:

1, 2, 3, 4, 5, and 6

Out of the 6 possible outcomes, there are only 2 that will get a number greater than or equal to 5. Write this as a fraction:

2/6

Simplify:

1/3

7 0

2 years ago

Expand the following:<br> a) x(x + 2)<br> b) x(2x - 5)<br> c) 2x(3x + 4)<br> d) 6x(x - 2)

TEA [102]

Answer:

<h2> $a. \: {x}^{2} + 2$ </h2>

<h2> </h2><h2> $b. \: 2 {x}^{2} - 5x$ </h2><h2> </h2><h2> $c. \: 6 {x}^{2} + 8x$ </h2><h3> </h3><h3> $d. \: 6 {x}^{2} - 12x$ </h3>

solution,

$a. \: x(x + 2) \\ \: \: = x \times x + 2 \times x \\ \: \: = {x}^{2} + 2x$

$b . \: x(2x - 5) \\ \: = x \times 2x - x \times 5 \\ \: \: = 2 {x}^{2} - 5x$

$c. \: 2x(3x + 4) \\ \: = 2x \times 3x + 2x \times 4 \\ \: \: = 6 {x}^{2} + 8x$

$d. \: 6x(x - 2) \\ \: \: = 6x \times x - 6x \times 2 \\ \: \: = 6 {x}^{2} - 12x$

<h2> </h2><h2 />

Hope this helps...

Good luck on your assignment..

4 0

2 years ago

Find the length of the curve y = 3/5x^5/3 - 3/4x^1/3 + 6 for 1 < = x < = 8. The length of the curve is . (Type an exact an

Mashutka [201]

Answer:

$\sqrt\frac{387}{20}$

Step-by-step explanation:

$Arc Length =\int\limits^a_b {\sqrt{1+(\frac{dy}{dx})^2 } } \, dx$

$y=\dfrac{3}{5}x^{\frac{5}{3}}- \dfrac{3}{4}x^{\frac{1}{3}}+6$

$\frac{dy}{dx} =x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}}$

$1+(\frac{dy}{dx})^2 }=1+(x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}})^2\\=1+(x^{\frac{4}{3}}-\dfrac{1}{2}+ \dfrac{1}{16}x^{-\frac{4}{3}})$

$=\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}}$

For the Interval $1\leq x\leq 8$

Length of the Curve $=\int\limits^8_1 {\sqrt{\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}} } } \, dx\\$

Using T1-Calculator

$=\sqrt\frac{387}{20}$

3 0

3 years ago