12÷3×5
4×5
20 m
so this is the answer
Answer:
the solution is where the two objects intersect ...
1) A line can completely miss the circle (no solutions is possible)
2) a line can "kiss" the circle at one point (one solution)
3) note that a line can not "bend"... it can touch one side of the circle pass
through the center and touch the circle in a second spot (going out) .. two solutions...
those are the three possibility that are in the question that was posted...
three check comments are true
Step-by-step explanation:
The volume of the prism is:
V = Ab * h
Where,
Ab: base area
h: prism height
The area of the base is:
Ab = (1/2) * (B + b) * (htr)
Where,
B: major base
b: minor base
htr: height of the trapeze
Substituting values:
Ab = (1/2) * (5 + 2) * (3)
Ab = 10.5
Then, the volume is:
V = (10.5) * (10)
V = 105 cm ^ 3
Answer:
The volume of the right prism is:
V = 105 cm ^ 3
I did it by the formula (a-b)^2=(a)^2-(2ab)+b^2
Hope it helps..
SAS congruence rule : two triangles are congruent if two sides and the included angle of one triangle are equal to the two sides and the included angle of the other triangle