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3 years ago

BRAINLIEST AND 20 POINTS

1 answer:

3 0

1. Which ratios form a proportion?
a. 4/5, 20/25 -----> 4/5, 4/5 Yes
b.8/12, 18/24 -----> 2/3, 3/4 No
c. 1/3, 7/24 ------> 8/24,7/24 No
d. 2/5, 6/16 -----> 2/5, 3/8 No

2.Which ratio forms a proportion with 9/15 = 3/5
a.3/6 = 2/3 No
b.2/3 No
c.12/30 = 2/5 No
d. 6/10 = 3/5 Yes

3.Which proportion has cross products of 5 x 24 and 8x15?
a. 5/8=15/24 ----> 5 * 24 = 8 * 15 Yes
b.5/24=8/15 ----> 5 * 15 = 8 * 24 No
c.8/24=15/5 ----> 5 * 8 = 15 * 24 No
d. 15/8=5/24 ----> 15 * 24 = 5 * 8 No

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PLEASE HELP!!!!

KIM [24]

1. 3rd one

2. f(x) = 7x - 5
f(2) = 7(2) - 5
f(2) = 14 - 5
f(2) = 9

3. c(n) = 0.75n - 0.25

4. (0,0)(2,4)
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3 years ago

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The sides, top, and bottom of a storage bin are made of wood. The storage bin measures 2 meters wide, 3 meters long, and 2 meter

Firlakuza [10]

I'm pretty sure that it's b. meters squared.

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3 years ago

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Create a proportion using the form = to represent the following word problem.

olga nikolaevna [1]

Answer:

60/100 and x/20 and x=12

Step-by-step explanation:

60 % of 20

60/100 = x/20

cross product

60 * 20 = 100x

divide by 100

1200/100 =x

12=x

Answer:60/100 = x/20 x= 12

hope it's right

5 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Cint%20t%5E2%2B1%20%5C%20dt" id="TexFormula1" title="\frac{d}{dx} \

Kisachek [45]

Answer:

$\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2} t^2+1 \ \text{dt} \ = \ 2x^5-8x^2+2x-2$

Step-by-step explanation:

$\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2} t^2+1 \ \text{dt} = \ ?$

We can use Part I of the Fundamental Theorem of Calculus:

$\displaystyle\frac{d}{dx} \int\limits^x_a \text{f(t) dt = f(x)}$

Since we have two functions as the limits of integration, we can use one of the properties of integrals; the additivity rule.

The Additivity Rule for Integrals states that:

$\displaystyle\int\limits^b_a \text{f(t) dt} + \int\limits^c_b \text{f(t) dt} = \int\limits^c_a \text{f(t) dt}$

We can use this backward and break the integral into two parts. We can use any number for "b", but I will use 0 since it tends to make calculations simpler.

$\displaystyle \frac{d}{dx} \int\limits^0_{2x} t^2+1 \text{ dt} \ + \ \frac{d}{dx} \int\limits^{x^2}_0 t^2+1 \text{ dt}$

We want the variable to be the top limit of integration, so we can use the Order of Integration Rule to rewrite this.

The Order of Integration Rule states that:

$\displaystyle\int\limits^b_a \text{f(t) dt}\ = -\int\limits^a_b \text{f(t) dt}$

We can use this rule to our advantage by flipping the limits of integration on the first integral and adding a negative sign.

$\displaystyle \frac{d}{dx} -\int\limits^{2x}_{0} t^2+1 \text{ dt} \ + \ \frac{d}{dx} \int\limits^{x^2}_0 t^2+1 \text{ dt}$

Now we can take the derivative of the integrals by using the Fundamental Theorem of Calculus.

When taking the derivative of an integral, we can follow this notation:

$\displaystyle \frac{d}{dx} \int\limits^u_a \text{f(t) dt} = \text{f(u)} \cdot \frac{d}{dx} [u]$
where u represents any function other than a variable

For the first term, replace $\text{t}$ with $2x$ , and apply the chain rule to the function. Do the same for the second term; replace

$\displaystyle-[(2x)^2+1] \cdot (2) \ + \ [(x^2)^2 + 1] \cdot (2x)$

Simplify the expression by distributing $2$ and $2x$ inside their respective parentheses.

$[-(8x^2 +2)] + (2x^5 + 2x)$
$-8x^2 -2 + 2x^5 + 2x$

Rearrange the terms to be in order from the highest degree to the lowest degree.

$\displaystyle2x^5-8x^2+2x-2$

This is the derivative of the given integral, and thus the solution to the problem.

6 0

2 years ago

What is 42.9 × 3.45 someone please

GaryK [48]

Answer:

148.005

Step-by-step explanation:

5 0

2 years ago