Answer:
A.)4x+8
C.)8x+12
Step-by-step explanation:
Same steps you did
What do you need help with?
6,050 before 6010 then 5080 after 5060 or basically any numbers that are greater than the one to the left of it :))
Answer:
Step-by-step explanation:
1. sin 30 = x/16
x= 16 sin 30
x = 8
2. cos 60 = 22/x
x = 22/cos 60
x = 44
3. tan 45 = x/19
x = 19 tan 45
x= 19
4. tan 16 = x/13
x = 13 tan 16
x= 3.73
5. sin 54 = x/45
x = 45 sin 54
x= 36.41
6. sin 35 = z/23
z = 23 sin 35
z = 13.19
Answer:
- f[1] = 3
- f[n] = 2·f[n-1] +4
- 108
Step-by-step explanation:
We observe that first differences of the given numbers are ...
10 -3 = 7
24 -10 = 14
52 -24 = 28
That is, each difference is 2× the previous one. This suggests an exponential relation that has a base of 2.
We notice that doubling a term doesn't give the next term, but gives a value that is 4 less than the next term. So, we can get the next term by doubling the previous one and adding 4.
Then our recursive relation is ...
f[1] = 3 . . . . the first term
f[n] = 2×f[n-1] +4 . . . . double the previous term and add 4
The next term is 2·52 +4 = 108.
