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2 years ago

7 yards = to how many feet

Mathematics

1 answer:

tino4ka555 [31]2 years ago

7 0

Answer:

21 Feet

Step-by-step explanation:

7 yards is equal to 21 feet

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Northern Bank has two types of account. Both accounts pay compound interest. Cash savings account Interest 2.5% per annum Shares

musickatia [10]

Answer: Ben will have the most interest.

Step-by-step explanation:

Ali after 3 years.

To use compound interest, the formula is:

= Investment * ( 1 + rate) ^ no. of periods

= 2,000 * ( 1 + 2.5%)³

= £‭2,153.78

Interest = Amount after 3 years - investment

= 2,153.78 - 2,000

= £153.78

Ben after 3 years.

= 1,600 * (1 + 3.5%)³

= £1,773.95

Interest = 1,773.93 - 1,600

= £173.93

4 0

2 years ago

10 (2)+1(2) how do u solve this problem?

Ilya [14]

Answer:22

Step-by-step explanation:

10x2+1x2=

20+2

=22

4 0

1 year ago

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WHAT ARE THE FOUR MAIN CYCLES THAT OCCUR IN NATURE PLZ HELP

maw [93]

Rock, Carbon, Water, Nitrogen

3 0

3 years ago

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Write the equation of the line in fully simplified slope-intercept form.

Lina20 [59]

Answer:

$y=-6x+2$

Step-by-step explanation:

Hi there!

Slope-intercept form: $y=mx+b$ where m is the slope and b is the y-intercept (the value of y when x=0)

1) Determine the slope (m)

$m=\displaystyle \frac{y_2-y_1}{x_2-x_1}$ where two points that fall on the line are $(x_1,y_1)$ and $(x_2,y_2)$

Given the graph, we determine which points we could use. For example, we could use the two points $(0,2)$ and $(1,-4)$ :

$m=\displaystyle \frac{-4-2}{1-0}\\\\m=\displaystyle \frac{-6}{1}\\\\m=-6$

Therefore, the slope of the line is -6. Plug this into $y=mx+b$ :

$y=-6x+b$

2) Determine the y-intercept (b)

Recall that the y-intercept occurs when x=0. Given the point (0,2), we know that the y-intercept is 2. Plug this into $y=-6x+b$ :

$y=-6x+2$

I hope this helps!

5 0

2 years ago

A ball is thrown from an initial height of 1 meter with an initial upward velocity of 15m/s. The ball's height h (in meters) aft

lakkis [162]

$\bf \stackrel{\textit{ball's height}~\hfill }{\stackrel{\downarrow }{h}=1+15t-5t^2}\implies \stackrel{\textit{ball's height}~\hfill }{\stackrel{\downarrow }{6}=1+15t-5t^2}\implies 0=-5+15t-5t^2 \\\\\\ ~~~~~~~~~~~~\textit{using the quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{5}t^2\stackrel{\stackrel{b}{\downarrow }}{-15}t\stackrel{\stackrel{c}{\downarrow }}{+5}=0 \qquad \qquad t= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}$

$\bf t=\cfrac{-(-15)\pm\sqrt{(-15)^2-4(5)(5)}}{2(5)}\implies t=\cfrac{15\pm\sqrt{225-100}}{10} \\\\\\ t=\cfrac{15\pm\sqrt{125}}{10}\implies t=\cfrac{15\pm\sqrt{5^2 \cdot 5}}{10}\implies t=\cfrac{\stackrel{3}{~~\begin{matrix} 15 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\pm ~~\begin{matrix} 5 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\sqrt{5}}{\underset{2}{~~\begin{matrix} 10 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}$

$\bf t=\cfrac{3\pm \sqrt{5}}{2}\implies t= \begin{cases} \frac{3+ \sqrt{5}}{2} \approx 2.618\\\\ \frac{3- \sqrt{5}}{2}\approx 0.382 \end{cases}$

8 0

2 years ago