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Mars2501 [29]
3 years ago
11

What is 41x+15= Pease!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
VikaD [51]3 years ago
6 0
56 i think the answer should me X=56
Naya [18.7K]3 years ago
4 0
Ur answer would be 56x
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The red car went 408 miles in 6 hours. The blue car went 365 miles in 5 hours. Which car had the fastest average speed?
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I hope this helps you

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Consider a population list x with μx=10 and SDx = 1. A second population list, y, with μy=10 and SDy=2, is added to the first li
Basile [38]

Answer:

The combined standard deviation is 1.58114.

Step-by-step explanation:

The formula to compute the combined standard deviations of two different data sets is:

SD_{c} =\sqrt{\frac{n_{X}S^{2}_{X}+n_{2}S^{2}_{Y}+n_{X}(\mu_{X}-\mu_{c})^{2}+n_{Y}(\mu_{Y}-\mu_{c})^{2}}{n_{X}+n_{Y}}

Here \mu_{c} is the combined mean given by:

\mu_{c}=\frac{n_{X}\mu_{X}+n_{Y}\mu_{Y}}{n_{X}+n_{Y}}

It is provided that the sample size is same for both the data sets, i.e.n_{X} = n_{Y}=n

Compute the combined mean as follows:

\mu_{c}=\frac{n_{X}\mu_{X}+n_{Y}\mu_{Y}}{n_{X}+n_{Y}}\\=\frac{(n\times10)+(n\times10)}{n+n}}\\=\frac{20n}{2n}\\ =10

Compute the combined standard deviation as follows:

SD_{c} =\sqrt{\frac{n_{X}S^{2}_{X}+n_{2}S^{2}_{Y}+n_{X}(\mu_{X}-\mu_{c})^{2}+n_{Y}(\mu_{Y}-\mu_{c})^{2}}{n_{X}+n_{Y}}}\\=\sqrt{\frac{(n\times1^{2})+(n\times2^{2})+(n(10-10))+(n(10-10))}{n+n}}\\=\sqrt{\frac{n+4n}{2n} } \\=\sqrt{\frac{5n}{2n} } \\=\sqrt{\frac{5}{2}} \\=1.58114

Thus, the combined standard deviation is 1.58114.

3 0
3 years ago
You rent 3 DVDs and 4 video games for $25. The following weekend, your friend rents 6 DVDs and 8 video games for $54. Which of t
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Wholesale cost of a telescope: $199.50; Markup: 50%, Discount: 30%,
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$2147.85

Step-by-step explanation:

199.5*.5=99.75

199.5+99.75=299.25

299.25*.3=89.775

299.25-89.775=209.475

209.475*.04=8.279

209.475+8.379=217.854

7 0
3 years ago
How many times 19 go into 36
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=1.894736842 and it keeps going

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