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boyakko [2]
3 years ago
5

Write the equation of the hyperbola centered at the origin, with a focus at (10, 0) and directrix at x = 125/10

Mathematics
1 answer:
vladimir1956 [14]3 years ago
7 0

Answer:

the equation of the hyperbola centered at the origin is

                                            \frac{x^2}{a^2}-\frac{y^2}{b^2}=1

                                          \frac{x^2}{\left(5\sqrt{5}\right)^2}-\frac{y^2}{\left(5i\right)^2}=1

Step-by-step explanation:

For a right-left facing hyperbola, the Foci (focus points) are defined:

\left(h+c,\:k\right),\:\left(h-c,\:k\right)

where c=\sqrt{a^2+b^2} is the distance form the center (h, k) to a focus.

So, the standard equation will be

                                                       \frac{x^2}{a^2}-\frac{y^2}{b^2}=1

  • As the equation of directrix at x = 125/10
  • Focus at (10, 0)

As the directrix is the line is

                                                x=\frac{a^2}{c}

As c = 10, and x = 125/10

So,

                                             \:x\times c=a^2

                                          \sqrt{x\times \:c}=a

                                        \sqrt{\frac{125}{10}\times \:10}=a

                                                  5\sqrt{5}=a

As

                                           a^2+b^2=c^2

                                           b^2=c^2-a^2

                                           b=\sqrt{c^2-a^2}

                                           b=\sqrt{\left(10\right)^2-\left(5\sqrt{5}\right)^2}

                                           b=\sqrt{100-125}

                                           b=\sqrt{-25}

                                           b=\sqrt{-1}\sqrt{25}

\mathrm{Apply\:imaginary\:number\:rule}:\quad \sqrt{-1}=i

                                           b=\sqrt{25}i

                                            b=5i

Therefore, the equation of the hyperbola centered at the origin is

                                            \frac{x^2}{a^2}-\frac{y^2}{b^2}=1

                                          \frac{x^2}{\left(5\sqrt{5}\right)^2}-\frac{y^2}{\left(5i\right)^2}=1

                                                 

Keywords: hyperbola, directrex, foci, equation of hyperbola

Learn more about equation of hyperbola from brainly.com/question/14295387

#learnwithBrainly

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