Simplify sqrt 3× sqrt 27

Mathematics

2 answers:

lidiya [134]3 years ago

7 0

[√3] * [√27] = √3 * √[9*3] = √3 *3√3 = 3 * 3 = 9,
or [√3] * [√27] = √[3*27] = √[81] = 9.

sleet_krkn [62]3 years ago

4 0

√3√27

=√(3*27)

=√81

=9

As 9*9=81.

----------------------

RULES:

√a√b=√ab

As (√a√b)²=((√a)²(√b)²)=√a√a√b√b=ab

When:

(√a√b)²=ab

√a√b=√ab

You might be interested in

How do you add and subtract fractions??

Semenov [28]

To add fractions they're suppose to have the same base or denominator then u add the top

To subtract it's the same but u subtract the top

5 0

3 years ago

Read 2 more answers

Which expression is equivalent??? help!

dexar [7]

Answer:

The equivalent expression for the given expression $\sqrt[3]{256x^{10}y^{7} }$ is

$4x^{3} y^{2}(\sqrt[3]{4xy} )$

Step-by-step explanation:

Given:

$\sqrt[3]{256x^{10}y^{7} }$

Solution:

We will see first what is Cube rooting.

$\sqrt[3]{x^{3}} = x$

Law of Indices

$(x^{a})^{b}=x^{a\times b}\\and\\x^{a}x^{b} = x^{a+b}$

Now, applying above property we get

$\sqrt[3]{256x^{10}y^{7} }=\sqrt[3]{(4^{3}\times 4\times (x^{3})^{3}\times x\times (y^{2})^{3}\times y )} \\\\\textrm{Cube Rooting we get}\\\sqrt[3]{256x^{10}y^{7} }= 4\times x^{3}\times y^{2}(\sqrt[3]{4xy}) \\\\\sqrt[3]{256x^{10}y^{7} }= 4x^{3}y^{2}(\sqrt[3]{4xy})$