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1 year ago

8

AABC goes through a sequence of transformations to form ABC. The sequence of transformations involved is a followed by a

1 answer:

lbvjy [14]1 year ago

7 0

Answer:

Step-by-step explanation:

what he said was he right answer

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Team B played three games and had an average of 13 hits in each game with 100 official at-bats. Three of the hits were home runs

Sophie [7]

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Pls mark brainliest!:)

5 0

2 years ago

F(x) = (x-3) (x+8) (x-11) <br> What are the zeros of the polynomial?

aalyn [17]

<span>hello :
</span>F(x) = (x-3) (x+8) (x-11)
F(x) =0
<span>x-3= 0 or x+8=0 or x-11 = 0
x=3 or x=-8 or x=11
</span><span>the zeros of the polynomialare : 3 , -8 , 11 </span><span>
</span>

6 0

2 years ago

The area of a rectangle is 42 ft squared, and the length of the rectangle is 5 ft more than twice the width. Find the dimensions

stira [4]

Answer:

<h3>Length = 12 ft</h3>

Width = $\frac{7}{2} ft$

Step-by-step explanation:

Given,

Area of rectangle = $42 \: {ft}^{2}$

Width = X

Length = 2x + 5

Now,

$x(2x + 5) = 42$

$2 {x}^{2} + 5x = 42$

$2 {x}^{2} + 5x - 42 = 0$

$2 {x}^{2} + 12x - 7x - 42 = 0$

$2x(x + 6) - 7(x + 6) = 0$

$(2x - 7)(x + 6) = 0$

Either

$2x - 7 = 0$

$2x = 0 + 7$

$2x = 7$

$x = \frac{7}{2}$

Or,

$x + 6 = 0$

$x = 0 - 6$

$x = - 6$

Negative value can't be taken.

So, width = $\frac{7}{2} ft$

Again,

Finding the value of length,

Length = $2x + 5$

$2 \times \frac{7}{2} + 5$

$7 + 5$

$12$

Length = 12 ft

7 0

2 years ago

Read 2 more answers

SVETLANKA909090 [29]

Answer:

A is a subset of B i believe that's the answer

8 0

2 years ago

What curve passes through the point (1 ,2) and has an arc length on the interval [2,6] given by Integral from 2 to 6 StartRo

Georgia [21]

Answer:

Step-by-step explanation:

Given

Length of curve

$L=\int_{2}^{6}\sqrt{1+64x^{-6}}dx$

Length of curve is given by

$L=\int_{a}^{b}\sqrt{1+\left ( \frac{\mathrm{d} y}{\mathrm{d} x}\right )^2}dx$ over interval a to b

comparing two we get

$\frac{\mathrm{d} y}{\mathrm{d} x}=8x^{-3}$

$dy=8x^{-3}dx$

integrating

$\int dy=\int 8x^{-3}dx$

$y=-4x^{-2}+C$

Curve Passes through (1,2)

$1=-4+C$

$C=5$

curve is

$y+\frac{4}{x^2}=5$

3 0

2 years ago