In this case, the continents are moving apart at a rate (velocity = 3 cm/y) and the distance for continent to move(distance= 500km). You are asked how long it will take(time). Then to answer this question you need to convert the 500km into the same unit as the velocity which was cm. The formula would be:

Distance = velocity x time
500km x 10^5 cm/km= 3cm/year x time
time= 5x 10^7 cm / (3cm/year)
time= 1.7 x 10^7 year or 17 million year

6 0

3 years ago

The Johnson family want to start a college fund for their daughter Gabriella. They put $63, 000 in to an account that grows at a

marissa [1.9K]

Answer:

34.13 years

Step-by-step explanation:

Given formula:

G(t)= 63000(1 + 0.0255/4)^4t

Need to find the value of t when G(t) = 150000

150000 = 63000( 1+ 0.0255/4)^4t
( 1+ 0.0255/4)^4t = 150000/63000
( 1+ 0.0255/4)^4t = 2.3809
4t* log( 1+ 0.0255/4) = log 2.3809
4t *0.00275983965 = 0.37674115501
t = 0.37674115501/(4*0.00275983965)
t = 34.13 years rounded

6 0

3 years ago

13.

Shalnov [3]

C is the answer, the line will intersect the original line. hope this helps good luck!!

3 0

3 years ago

You deposit $300 in a savings account that pays 6% interest compounded semiannually. How much will you have at the middle of the

Otrada [13]

Answer:

Please check the explanation.

Step-by-step explanation:

a) How much will you have at the middle of the first year?

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 0.5 years

Total amount = A = ?

Using the formula

$A\:=\:P\left(1+\frac{r}{n}\right)^{nt}$

substituting the values

$A=300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(0.5\right)}$

$A=300\cdot \frac{2.06}{2}$

$A=\frac{618}{2}$

$A=309$ $

Therefore, the total amount accrued, principal plus interest, from compound interest on an original principal of $ 300.00 at a rate of 6% per year compounded 2 times per year over 0.5 years is $ 309.00.

Part b) How much at the end of one year?

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 1 years

Total amount = A = ?

Using the formula

$A\:=\:P\left(1+\frac{r}{n}\right)^{nt}$

so substituting the values

$A\:=\:300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(1\right)}$

$A=300\cdot \frac{2.06^2}{2^2}$

$A=318.27$ $

Therefore, the total amount accrued, principal plus interest, from compound interest on an original principal of $ 300.00 at a rate of 6% per year compounded 2 times per year over 1 year is $ 318.27.

7 0

3 years ago