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OlgaM077 [116]
3 years ago
12

4. Two more than a certain number is 15 less 7 8 than the product of and the number.

Mathematics
1 answer:
Serggg [28]3 years ago
4 0

<u>Answer</u><u>:</u>

Equation: x + 2 = 7/8x - 15

Solution: x = -136

<u>Explanation</u><u>:</u>

x + 2 = 7/8x - 15

2 + 15 = 7/8x - x

17 = 7/8x - 8/8x

17 = -1/8x

17 × -8 = x

-136 = x

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irinina [24]

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2502.1

Step-by-step explanation:

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The equation of a circle is (x - 4)2 + (y - 4)2 = 9. The point (4, 1) is on the circle.
Alika [10]

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3 0
1 year ago
What’s the answer???(SOMEONE PLEASE HELP ME)
sweet [91]

Answer:

Let's solve for f.

fx=

4x−3

x−10

Step 1: Multiply both sides by x-10.

fx2−10fx=4x−3

Step 2: Factor out variable f.

f(x2−10x)=4x−3

Step 3: Divide both sides by x^2-10x.

f(x2−10x)

x2−10x

=

4x−3

x2−10x

f=

4x−3

x2−10x

Answer:

f=

4x−3

x2−10x

Let's solve for g.

gx=

2x−8

x−10

Step 1: Multiply both sides by x-10.

gx2−10gx=2x−8

Step 2: Factor out variable g.

g(x2−10x)=2x−8

Step 3: Divide both sides by x^2-10x.

g(x2−10x)

x2−10x

=

2x−8

x2−10x

g=

2x−8

x2−10x

Answer:

g=

2x−8

x2−10x



Step-by-step explanation:


7 0
3 years ago
Find the value of k such the -2/3 is the zero of the function f(x)=4x+k/7
Mashutka [201]
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3 0
3 years ago
How to do substitution or elimination
Levart [38]
I: y=(1/2)x+5
II: y=(-3/2)x-7

substitution:
fancy word for insert the definition of one variable in one equation into the other
-> isolate a variable, luckily y is isolated (even in both equations) already
-> substitute y of II into I (=copy right side of II and replace y in I with it):

(-3/2)x-7=(1/2)x+5
-3x-14=x+10
-3x-24=x
-24=4x
-6=x

-> insert x back into I (or II):
y=(1/2)x+5
=(1/2)*(-6)+5
=-3+5=2

elimination: subtract one equation from the other to eliminate a variable, again y is already isolated->no extra work required

I-II:
y-y=(1/2)x+5-[(-3/2)x-7]
0=(1/2)x+5+(3/2)x+7
0=(4/2)x+12
-12=2x
-6=x

-> insert x back into I (or II):
y=(1/2)x+5
=(1/2)*(-6)+5
=-3+5=2
8 0
3 years ago
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