QN = 28
Solution:
Given MNPQ is a parallelogram.
QT = 4x + 6 and TN = 5x + 4
To find the length of QN:
Let us solve it using the property of parallelogram.
Property of Parallelogram:
Diagonals of the parallelogram bisect each other.
Therefore, QT = TN
⇒ 4x + 6 = 5x + 4
Arrange like terms together.
⇒ 6 – 4 = 5x – 4x
⇒ 2 = x
⇒ x = 2
Substitute x = 2 in QT and TN
QT = 4(2) + 6 = 14
TN = 5(2) + 4 = 14
QN = QT + TN
= 14 + 14
QN = 28
The length of QN is 28.
A
Did the test and past the grade your in
<span>The LCM is 21624..
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∠1 = 50°
∠2=70°
If ∠3 is exterior ansgle with respect to ∠1 and ∠2, ∠3 must be ∠1+∠2 = 50°+70° =120°..Whereas, the interior angle with ∠3 will be 180°-120°=60°
The answer is D because range is the smallest amount and the largest amount on a graph. So in your case -2 and +4 is the outliers.
