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VARVARA [1.3K]
3 years ago
13

Evaluate 6 + 4/a + b/3 when a = 4 and b = 3.

Mathematics
1 answer:
GREYUIT [131]3 years ago
8 0

The answer to your problem would be 8.

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Please help. 21 points
Eduardwww [97]

Answer:

4/5 ÷3/5

4/5×5/3(any time one is dividing a fraction, the dominator would go up while the numerator would come down).

=4/3

4 0
3 years ago
Fraction written problems<br> 6th grade
Sholpan [36]

Answer:

what??????????

Step-by-step explanation:

4 0
3 years ago
Two weeks in a row, the golf course hosts a group of golfers. The second week had 10 more golfers than the first week. Use the d
Trava [24]

Answer:

Option A.

Step-by-step explanation:

From the first dot plot the given data set for week 1 is

62, 68, 68, 68, 69, 70, 70, 72, 72, 72, 75, 75, 76, 78, 78, 80, 80, 80, 89, 89

Divide the data in 4 equal parts.

(62, 68, 68, 68, 69), (70, 70, 72, 72, 72), (75, 75, 76, 78, 78), (80, 80, 80, 89, 89)

Range=Maximum-Minimum=89-62=27

Median=\frac{72+75}{2}=73.5

Mean=\frac{\sum x}{n}=\frac{1491}{20}=74.55

From the second dot plot the given data set for week 2 is

62, 68, 68, 68, 69, 70, 70, 72, 72, 72, 75, 75, 76, 78, 78, 80, 80, 80, 85, 86, 86, 86, 88, 88, 88, 88, 89, 89, 89, 89

Divide the data in 4 equal parts.

(62, 68, 68, 68, 69, 70, 70), 72, (72, 72, 75, 75, 76, 78, 78), (80, 80, 80, 85, 86, 86, 86), 88, (88, 88, 88, 89, 89, 89, 89)

Range=Maximum-Minimum=89-62=27

Median=\frac{78+80}{2}=79

Mean=\frac{\sum x}{n}=\frac{2364}{30}=78.8

The range for Week 1 is equal to the range for Week 2.

The median for Week 2 is more than the median for Week 1.

The mean for Week 2 is more than the mean for Week 1.

Therefore, the correct option is A.

6 0
3 years ago
Miguel finds a scrapbook that can hold 200 stamps.if Miguel has 2,000 stamps in all,how many scrapbooks will he need to buy for
ycow [4]

Answer: 10

Step-by-step explanation: 2,000 divided by 200 is 10.

8 0
3 years ago
Least to greatest. 26.2, 262%, 2 3/5 (two and three fifths)
9966 [12]

Answer:

Step-by-step explanation:

BACD

3 0
3 years ago
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