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2 years ago

10

This is dealing with graphing functions

1 answer:

Mnenie [13.5K]2 years ago

6 0

Can you add the graphs? EDIT: When I graph it this is what I get.

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Plot a point on the coordinate plane to represent each of the ratio values in the table. Time (h) Distance (km) able displaying

Effectus [21]

Answer:

Refer the attached graph.

Step-by-step explanation:

Given : Time (h) Distance (km) able displaying Time in hours in one column and Distance in kilometers in the other. The time column contains 1, 3, 6, and 9. The distance column contains 2, 6, 12, and 18.

To plot : The points on the coordinate plane.

Solution :

Time is independent variable so it is taken on x-axis.

Distance is taken on y-axis.

x y

1 2

3 6

6 12

9 18

When we plot these points in the coordinate plane, we get a linear equation.

The linear equation form is $y=2x$

Refer the attached graph.

4 0

2 years ago

The manufacturer's price for a cooler is $28.50 A camping store that buys the coolers sells them for $40.76 What is the approxim

Nutka1998 [239]

The percent of the increase is

$I=\frac{N-O}{O}\times100$

I is the increasing value

N is the new value

O is the original value

The price of the cooler is $28.50, then

O = 28.50

The selling price of the cooler is $40.76, then

N = 40.76

We will substitute them in the rule above to find I

$I=\frac{40.76-28.50}{28.50}\times100$

Let us calculate it

I = 43.0175 %

Round it to the nearest percent

I = 43%

The answer is D

6 0

11 months ago

Anyone, please help me please answer my question because I have to pass this tomorrow morning:(

Wittaler [7]

Step-by-step explanation:

If you need help with how I got my answer, you can ask me.

$\frac{2yx {}^{ - 4} }{(x {}^{ - 4}y {}^{4}) {}^{3} \times 2x {}^{ - 1}y {}^{ - 3} }$

$\frac{2yx {}^{ - 4} }{x {}^{ - 12}y {}^{12} \times 2x {}^{ - 1}y {}^{ - 3} }$

$\frac{2y x {}^{ - 4} }{2x {}^{ - 13} y {}^{ - 9} }$

$= x {}^{9} y {}^{ - 8}$

$= \frac{x {}^{9} }{y {}^{8} }$

12.

$( \frac{2u {}^{ 4} }{ - u {}^{2}v {}^{ - 1} \times 2uv {}^{ - 4} } ) {}^{ - 1}$

$( \frac{2u {}^{4} \times 1 }{ - 2 {u}^{3}v {}^{ - 5} } ) {}^{ - 1}$

$( - u v {}^{ 5} ) {}^{ - 1}$

$= - u {}^{ - 1} v {}^{ - 5} = - \frac{ 1}{uv {}^{5} }$

13.

$- \frac{2m {}^{4}n {}^{ - 1} }{( - m {}^{2}n {}^{ - 2}) {}^{ - 1} \times - nm {}^{ - 3} }$

$- \frac{2m {}^{4}n {}^{ - 1} }{ - m {}^{ - 2} n {}^{2} \times - nm {}^{ - 3} }$

$- \frac{2m {}^{4} n {}^{ - 1} }{m {}^{ - 5}n {}^{3} } = - 2m {}^{9} n {}^{ - 4}$

$= - \frac{2m {}^{9} }{n {}^{4} }$

14.

$( \frac{x {}^{3}y {}^{ - 4} }{ - {x}^{2} y {}^{ - 3} \times yx {}^{0} } ) {}^{3}$

$( \frac{x {}^{3}y {}^{ - 4} }{ - {x}^{ - 2}y {}^{ - 2} } ) {}^{3}$

$( - {x}^{5} y {}^{ - 2} ) {}^{3} = - x {}^{15} y {}^{ - 6}$

$- \frac{x {}^{15} }{ {y}^{6} }$

15.

$- \frac{yx {}^{4} \times - {y}^{3} z { }^{ - 4} }{(z {y}^{2} ) {}^{4} }$

$- \frac{ - y {}^{4} x {}^{4} z {}^{ - 4} }{ {z}^{4} y {}^{8} } = - y {}^{4} x {}^{4} z {}^{ - 8} = - \frac{(xy) {}^{4} }{ {z}^{8} }$

16.

$\frac{h {}^{7}j {k}^{4} }{4h {}^{4} } = \frac{1}{4} h {}^{3} = \frac{h {}^{3} jk {}^{4} }{4}$

6 0

2 years ago

In preparing a certain ointment, a pharmacist used 28.35 g of zinc oxide instead of the 31.1 g called for. Calculate the percent

Vilka [71]

Answer: 9.70%

Step-by-step explanation:

The formula to find the percentage error is given by :-

$\%\text{ error}=\dfrac{|\text{Estimate-Actual}|}{\text{Actual}}\times100$

Given : Actual mass of zinc oxide used by pharmacist = 28.35 g

Estimated mass of zinc oxide used by pharmacist =31.1 g

Now, $\%\text{ error}=\dfrac{|31.1-28.35|}{28.35}\times100$

i.e. $\%\text{ error}=\dfrac{2.75}{28.35}\times100$

i.e. $\%\text{ error}=9.70017636684\approx9.70\%$

Hence, the percentage of error on the basis of the desired quantity.= 9.70%

5 0

2 years ago

PLEASE ANSWERRRRRRRRRR

Jet001 [13]

Step-by-step explanation:

D. Both charges must be different.

Because, like charges repel each other and different charges attract each other.

5 0

2 years ago

Read 2 more answers