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3 years ago

This is dealing with graphing functions

Mathematics

1 answer:

Mnenie [13.5K]3 years ago

6 0

Can you add the graphs? EDIT: When I graph it this is what I get.

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Paul's mom sent him to the grocery store with $10 to buy bread and cheese for sandwiches. Paul picked out a loaf of bread that c

lutik1710 [3]

Given:

Total amount = $10

Cost of loaf of bread = $3.25

Cost of cheese = $5.99 per pound

Each slice weights = 0.04 pounds.

To find:

The inequality for the number of slices that Paul can afford to buy.

Solution:

Let x be the number of slices that Paul can afford to buy.

Weight of on slice is 0.04 pounds. So, weight of x slices is 0.04x pound.

Cost of cheese = $5.99 per pound

So, total cost of cheese for x slices = $5.99 × 0.04x

Now, Paul has $10 to buy bread and cheese for sandwiches. Cost of loaf of bread is $3.25.

$3.25+(5.99\times 0.04x)\leq 10$

$0.2396x\leq 10-3.25$

$0.2396x\leq 6.75$

Divide both sides by 0.2396.

$x\leq \dfrac{6.75}{0.2396}$

$x\leq 28.172$

The maximum integer value of x is 28.

Therefore, the required inequity is $3.25+(5.99\times 0.04x)\leq 10$ and 28 number of slices Paul can afford to buy.

6 0

3 years ago

Addition 1.4 +1.8 what is the answer

zepelin [54]

Simple. The answer is 3.2.

3 0

3 years ago

F(x)=2x^2+4x+5<br> Find : f(a)=

VladimirAG [237]

Answer:

f(a) = 2a^2 + 4a + 5

Step-by-step explanation:

You just need to replace the "x" with the "a".

7 0

3 years ago

Find the area A of polygon ABCDEFG with the given vertices.

zhuklara [117]

Ffhgfdhjehhdjdbdrvddjdbfb

5 0

3 years ago

A drawer contains 3 white shirts, 2 blue shirts, and 5 gray shirts. A shirt is randomly

shutvik [7]

Answer:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = $\frac{1}{4}$

Step-by-step explanation:

Given that

3 white, 2 blue and 5 gray shirts are there.

To find:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = ?

Solution:

Here, total number of shirts = 3+2+5 = 10

First of all, let us learn about the formula of an event E:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

$P(First\ White) = \dfrac{\text{Number of white shirts}}{\text {Total number of shirts left}}$

$P(First\ White) = \dfrac{3}{10}$

Now, this shirt is set aside.

So, total number of shirts left are 9 now.

$P(First\ White\ and\ second\ gray) = P(First White) \times P(Second\ Gray)\\\Rightarrow P(First\ White\ and\ second\ gray) = P(First White) \times \dfrac{\text{Number of gray shirts}}{\text{Total number of shirts left}}\\\\\Rightarrow P(First\ White\ and\ second\ gray) = \dfrac{3}{10} \times \dfrac{5}{9}\\\Rightarrow P(First\ White\ and\ second\ gray) = \dfrac{1}{2} \times \dfrac{1}{2}\\\Rightarrow P(First\ White\ and\ second\ gray) = \bold{\dfrac{1}{4} }$

So, the answer is:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = $\frac{1}{4}$

4 0

3 years ago