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Zigmanuir [339]
3 years ago
6

What is the solution to the following equation? (5x-2)^2=10

Mathematics
1 answer:
GaryK [48]3 years ago
7 0
Take the square root of both sides to get rid of parenthasees, remember to get the positive and negative root
5x-2=+/-√10
add 2 to both sides
5x=2+/-√10
divide by 5
x=\frac{2+/- \sqrt{10} }{y}

x= \frac{2+ \sqrt{10} }{y} or \frac{2- \sqrt{10} }{y}

aprox
x=1.03246 or -0.232456
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The time T required to repair a machine is an exponentially distributed random variable with mean 10 hours.
Firdavs [7]

It can be expected about 36.79% of chance that repair time exceeds

The probability that a repair time exceeds  15 hours is 0.3679

What is the exponential distribution?

It explains about the time between events or the distance between two random events is termed the exponential distribution. Here, the occurrence of the events is continuous and also independent. Moreover, the average rate is constant.

The cumulative distribution function of T is obtained below:

From the information given, let the random variable T be the required time to repair a machine follows exponential distribution with parameter λ
with mean. 1/2 hours

That is,  E(x) =  1/2 hours.
The parameter of the random variable T is,
E(x) =  1/λ
λ = 1/E(x)
= 1/(1/2)
= 2

The probability density function of T is,
f(t) = \left \{ {{2e^{-2t} \ \ \ t > 0}  \  \atop {0} \ \ \ elsewhere} \ \right.
The cumulative density function of T is,
FT(t) = P(T <= t)

= 1 - e^{- \lambda t}

= 1 - e^{- 2t}
The CDF of T is,
P(T <= t)  = 1 - e^{- 2t}    0 <= T <= ∞
        = 0          otherwise
to obtain the probability that a repair time exceeds

1/2 hours.
(a) The probability that a repair time exceeds 1/2 hours.
From the given information, the CDF of T is,
P(T <= t)  = 1 - e^{- 2t}    0 <= T <= ∞
        = 0          otherwise

The required probability is,
P(T <= 1/2)  = 1 - P(T <= 1/2)
        = 1 - [  = 1 - e^{- 2(1/2)} ]
       = e^{-1}
= 0.3679

om total probability. It can be expected about 36.79% of chance that repair time exceeds

P(X => x)  = 1 - P(X < x)
to obtain the probability that a repair takes at least 12.5 hours given that its duration exceeds 12 hours.

(b), The probability that a repair takes at least 12.5 hours given that its duration exceeds 12 hours is obtained below:
From the given information, the CDF of T is,
P(T <= t)  = 1 - e^{- 2t}    0 <= T <= ∞
        = 0          otherwise
The required probability is,
P = P(T => 12.5∩T>12) / P(T>12)
= e^{- 25 + 24}

= e^{- 1}
= 0.3679
The probability that a repair takes at least 12.5 hours given that its duration exceeds 12 hours is obtained by dividing the
P = P(T => 12.5∩T>12) / P(T>12)
with
P(T>12).

It can be expected about 36.79% of chance that a repair takes at least 12.5 hours given that its duration exceeds 12 hours.

Hence, It can be expected about 36.79% of chance that repair time exceeds,

The probability that a repair time exceeds  15 hours is 0.3679

To learn more about the product of the fraction visit,
brainly.com/question/22692312
#SPJ4

7 0
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Help with top one? thankss
AnnyKZ [126]

Answer:

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Step-by-step explanation:

11.85/3 = half pound = $3.95

3.95x2 = 7.9 = 1 pound

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3 years ago
What is the number word of this 675,356,017
Stella [2.4K]

~Hello There!~

Six hundred and seventy five million, three hundred and fifty six thousand and seventeen

Hope This Helps You!

Good Luck :)

Have A Great Day ^_^

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Simplify the fraction so it’s easier to work with.
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Make ⁴/₃ equal to ⁸/x because since you want to find the new width, you need to make it equal to a new fraction.
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Cross multiply.
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Find the equation of a circle with center at (5, 6) and radius 8.
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Answer:

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Step-by-step explanation:

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