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2 years ago

PLease helpppp PLEASEE HELLLLP i dont get it

Mathematics

1 answer:

Agata [3.3K]2 years ago

8 0

Answer:

x = 100°

Step-by-step explanation:

x = 100° because the two angles are corresponding.

If my answer is incorrect, pls correct me!

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-Chetan K

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No referencial está representado o círculo trigonométrico e um ponto A, resultante da intersecção da circunferência como lado ex

Anna35 [415]

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3 years ago

Y= -2 (x+2)^2-8<br>vertex=?<br>how to graph?

MissTica

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3 years ago

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How do I solve for X<br> ax+bx=c

Nezavi [6.7K]

Combine like terms the solve. For example:

5x + 20x = 100
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3 years ago

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Karen gets a gas bill. The cost of the gas before the VAT was added was £361.20.

insens350 [35]

The cost of gas bill including VAT is 379.26.

Value-Added Tax (VAT) is a tax, which is payable on sales of goods or services within the territory of the Member States of the EU.

Given:

Cost of the gas before the VAT was added was £361.20.

VAT = 5%

Thus, cost of bill including VAT is

=361.20.*1.05

=379.26.

Learn more about VAT here:

brainly.com/question/20628016

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2 years ago

12% of children are nearsighted, but this condition often is not detected until they go to kindergarten. A school district tests

Klio2033 [76]

Answer:

There is a 34.60% probability that 0 or 1 of them is nearsighted.

Step-by-step explanation:

For each children, there are only two possible outcomes. Either they are nearsighted, or they are not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem, we have that:

12% of children are nearsighted. This means that $p = 0.12$ .

A school district tests all incoming kindergarteners' vision. In a class of 18 kindergarten students, what is the probability that 0 or 1 of them is nearsighted?

There are 18 students, so $n = 18$