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attashe74 [19]
3 years ago
7

How much do you save if you get 25% off a $30 book

Mathematics
2 answers:
erica [24]3 years ago
7 0

Answer:

$7.50

Step-by-step explanation:

Thus, a product that normally costs $30 with a 25 percent discount will cost you $22.50, and you saved $7.50. You can also calculate how much you save by simply moving the period in 25.00 percent two spaces to the left, and then multiply the result by $30 as follows: $30 x .25 = $7.50 savings.

Sliva [168]3 years ago
5 0

Answer:

$7.50

Step-by-step explanation:

30/4 = $7.50

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Given that the two triangles are similar, solve for x if AU = 20x + 108, UB = 273, BC = 703, UV = 444, AV = 372 and AC = 589. Yo
Arlecino [84]

If two triangles are similar then the corresponding sides are in proportion. Thus,

AB / AU = BC / UV = AC / AV

AB / (20x+108) = 703 / 444

Where AB is equivalent to:

AB = AU + UB

AB = 20x + 108 + 273

AB = 20x + 381

Therefore going back to the first equation:

(20x + 381) / (20x + 108) = 703/444

444 (20x + 381) = 703 (20x + 108)

8880x + 169164 = 14060x + 75924

14060x - 8880x = 169164 – 75924

5180 x = 93240

x = 93240 / 5180

<span>x = 18</span>

4 0
3 years ago
Plz find the iii (3).plz plz plz
kirza4 [7]

Answer:

Rs 937.50

Step-by-step explanation:

Rs 750 for 4 years at 6 1/4% interest:

Simple interest is found using i = p*r*t, where p is the principal, r is the interest rate as a decimal fraction, and t is the number of years.

Here, i = (Rs 750)*0.0625*4 = Rs 187.50

The amount (that is, principal plus simple interest) will be:

Rs 750 + Rs 187.50 = Rs 937.50

8 0
2 years ago
The equation of motion for a weight suspended from a particular spring is given by p(t)=2sint3+5cost3p(t)=2sin⁡t3+5cos⁡t3, where
daser333 [38]
The given displacement at time, t, is
p(t) = 2 sin(t³) + 5 cos(t³)

The initial equilibrium position is
p(0) = 5

To determine future equilibrium postions, define
f(t) = p(t) - 5 = 2 sin(t³) + 5 cos(t³ - 5
The derivative of f(t) is
f'(t) = (3t²)[2 cos(t³) - 5sin(t³)]

Equilibrium is established when f(t) = 0.
To solve this equation numerically, we shall use the Newton-Raphson method, given by.
t(n+1) = t(n) - f[t(n)]/f'[(t(n)], n=0,1,2, ...,

As a guess, let (0) = 1.
The iterative solution for t is shown below.

  n         t(n)
 ---   -----------
   0   1.0000
   1    0.9344
   2   0.9147
   3   0.9130
   4   0.9130

The solution converges rapidly to t = 0.913 s.
The graphical solution (shown below) confirms the numerical solution.

Answer:
The weight first reaches the equilibrium position in 0.913 sec.

4 0
3 years ago
How do you subtract 25-2.65
Rasek [7]
25.00
-2.65

That is how you subtract 25 from 2.65
3 0
3 years ago
Read 2 more answers
Simplify 6/6^1/4 rational exponents
White raven [17]

Answer:

we conclude that:

\frac{6}{6^{\frac{1}{4}}}=6^{\frac{3}{4}}

Step-by-step explanation:

Given

The expression is

  • \frac{6}{6^{\frac{1}{4}}}

To determine

Simplify the expression

Simplifying the expression

\frac{6}{6^{\frac{1}{4}}}

Apply the exponent rule:   \frac{x^a}{x^b}=x^{a-b}

\frac{6}{6^{\frac{1}{4}}}=6^{1-\frac{1}{4}}

Subtract the numbers:   1-\frac{1}{4}=\frac{3}{4}

     =6^{\frac{3}{4}}

Therefore, we conclude that:

\frac{6}{6^{\frac{1}{4}}}=6^{\frac{3}{4}}

7 0
3 years ago
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