Let x = number of students in each of the remaining rows
266 = (10 x 20) + (5 x 8) + 2x
266 - (10 x 20) - (5 x 8) = 2x
266 - 200 - 40 = 2x
26 = 2x
x = 26/2
x = 13
Answer:
140 toy cars
Step-by-step explanation:
The ratio of Ed's toy car to Pete's toy car is initially given as 5:2
Ed gave Pete a total number of 30 cars
Let x represent the greatest common factor that exists between both number
Number of Ed's car is represented as 5x
Number of Pete car is represented as 2x
Since they each have an equal number of cars which is 30 then we can solve for x as follows
5x-30=2x+30
Collect the like terms
5x-2x= 30+30
3x= 60
Divide both sides by the coefficient of x which is 3
3x/3=60/3
x=20
Ed's car is 5x, we substitute 20 for x
5(20)
= 100 cars
Pete car is 2x,we substitute 20 for x
2(20)
= 40 cars
Therefore, the total number of cars can be calculated as follows
= 100+40
= 140 toy cars
Hence they have 140 toy cars altogether
Answer:
RANGE=21
Step-by-step explanation:
Least to greatest is KEY!
Pretty sure it’s infinitely many solutions
Answer:
The inequality that represents the age of the group, "x", is: 
Step-by-step explanation:
To express this problem in an inequality we will attribute the age of the members on the group with the variable "x". There are two available information about "x", the first states that every member of the group is older than 17 years, therefore we can create a inequality based on that:

While the second data from the problem states that none of than is older than 54 years old, this implies that they can be at most that old, therefore the inequality that represents this is:

In order for both to be valid at the same time x must be greater than 17 and less or equal to 54, therefore we finally have:
