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2 years ago

What is the length of CD to the nearest 10th?

Mathematics

1 answer:

Snezhnost [94]2 years ago

3 0

Answer:

$\huge \boxed{\mathrm{10.3 \ units}}$

Step-by-step explanation:

To solve for <em>CD</em>, we can create a right triangle.

Where <em>CD</em> becomes the hypotenuse.

The length of the base of the triangle is 9 units.

The length of the height of the triangle is 5 units.

Apply Pythagorean theorem to solve for the hypotenuse.

$\sf hypotenuse = \sqrt{(base )^2 +(height )^2 }$

$c=\sqrt{9^2 +5^2 }$

$c=\sqrt{106}$

$c \approx 10.29$

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2 years ago

I need help trying to figure this out I think I have and answer but I want to make sure.

yKpoI14uk [10]

Answer:

Step-by-step explanation:

The mean is calculated as

mean = $\frac{frequency(midpoint)}{frequency}$

let x be the missing frequency, then

Total frequency × midpoint

= (16 × 2) + 7x + (20 × 12) + (10 × 17) = 32 + 7x + 240 + 170 = 442 + 7x

Total frequency = 16 + x + 20 + 10 = 46 + x, thus

$\frac{242+7x}{46+x}$ = 8.5 ( cross- multiply )

442 + 7x = 8.5(46 + x)

442 + 7x = 391 + 8.5x ( subtract 8.5x from both sides )

442 - 1.5x = 391 ( subtract 442 from both sides )

- 1.5x = - 51 ( divide both sides by - 1.5 )

x = 34

The missing frequency is 34

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2 years ago

How many significant numbers are in 343?

Alona [7]

Answer:

there are 3.

Step-by-step explanation:

3, 4 and 3 are all significant numbers

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2 years ago

Teresa earned scores of 88, 84, 88 points and 91 points on 4 test what is the lowest score she can get on the fifth test and sti

Usimov [2.4K]

Answer:

99 points

Step-by-step explanation:

Average of a data a is the sum of the data divided by the number of data.

Average = sum of data ÷ number of data

A = T/n .....1

For the average of 5 test to be 90.

The total sum of score must be;

Number of tests n = 5

Average A = 90

Substituting into equation 1

90 = T/5

T = 90×5 = 450 points

The total score must be equal to 450 point to have an average of 90 points

The sum of the first four test is;

88+84+88+91 = 351

Let x represent the first score,

351 + x = 450

x = 450 - 351

x = 99 points

The minimum score she can get in the fifth test is 99 points

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2 years ago

In 1985, there were 285 cell phone subscribers in Arlington. The number of subscribers increased by 75% per year since 1985. Fin

ANTONII [103]

Answer:

The number of subscribers in 2008 is 110,845,988

Step-by-step explanation:

The number of cell phone subscribers in Arlington, in t years after 1985, can be modeled by the following equation.

$N(t) = N(0)(1+r)^{t}$

And which N(0) is the number of subscribers in 1985 and r is the rate it increases per year, as a decimal.

In 1985, there were 285 cell phone subscribers in Arlington.

This means that $N(0) = 285$

The number of subscribers increased by 75% per year since 1985.

This means that $r = 0.75$

$N(t) = 285(1.75)^{t}$

Find the number of subscribers in 2008.

2008 is 2008-1985 = 23 years after 1985. So we have to find N(23).

$N(23) = 285(1.75)^{23} = 110,845,988$

The number of subscribers in 2008 is 110,845,988

8 0

2 years ago