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3 years ago

Solve for s. 0.5s+1=7+4.5s

Mathematics

2 answers:

ludmilkaskok [199]3 years ago

7 0

1=7+4.5s-0.5s

1=7+4s

1-7=4s

-6=4s

-6/4=s

-3/2=s

s= -3/2.

MrMuchimi3 years ago

6 0

S Equals -1.5

Workout Im gonna use X becuase i get confused with s and 5

0.5x+1=7+4.5x

Subtract 4.5x from 0.5x

-4x+1=7

Subtract 1 from 7

-4x=6

Divide -4x into 6 and the answer will be -1.5

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3 years ago

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PLEASE HELP

Nookie1986 [14]

For the square with side length n, the diagonal measures:

$d = \sqrt{2} *n$

<h3>How to get the length of the diagonal?</h3>

The sidelength of the square is n, and we want to get the length of the diagonal d.

Notice that the diagonal is the hypotenuse of a right triangle whose catheti measure n.

Then we can use the Pythagorean theorem, which says that the square of the hypotenuse is equal to the sum of the squares of the cathetus;

$d^2 = n^2 + n^2\\\\d^2 = 2n^2\\\\d = \sqrt{2n^2} \\\\d = \sqrt{2}*n$

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2 years ago

What integers are closet to the number 95

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3 years ago

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Find the area of the triangle with the given base and height. b = 3 m and h = 10 1/2 m

svetoff [14.1K]

Statement:

The base of a triangle is 3m and its height is $10 \frac{1}{2}$ m.

To find out:

The area of the triangle.

Solution:

Given, base = 3m, height = $10 \frac{1}{2}$ m
We know,

$\sf \: area \: \: of \: \: a \: \: triangle = \frac{1}{2} \times base \: \times height$

Therefore, the area of the triangle

$\sf = (\frac{1}{2} \times 3 \times 10 \frac{1}{2} ) {m}^{2} \\ \sf = ( \frac{1}{2} \times 3 \times \frac{21}{2} ) {m}^{2} \\ = \sf \frac{63}{4} {m}^{2} \\ = \sf 15\frac{3}{4} {m}^{2}$

Answer:

The area of the triangle is $\sf \: 15 \frac{3}{4} {m}^{2}$

Hope you could understand.

If you have any query, feel free to ask.

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3 years ago

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