Ask question

Ask question

All categories

3 years ago

11

Brynne has 13 books she has 8 more books than games how many game does Brynne have

2 answers:

GalinKa [24]3 years ago

7 0

The answer is she has 5 more books

vagabundo [1.1K]3 years ago

3 0

Answer:

5

Step-by-step explanation:

You might be interested in

Is this true or false need answer asap

VLD [36.1K]

Answer: True

Step-by-Step Explanation:

=> 2x + 3y = -7 (Eq. 1)
=> -x = 2y (Eq. 2)
=> x = 1, y = -3

Substitute values of ‘x’ and ‘y’ in Eq. 1 :-

=> 2x + 3y = -7
= 2(1) + 3(-3) = -7
= 2 + -9 = -7
=> -7 = -7
=> LHS = RHS

Therefore, it is a Solution.

3 0

2 years ago

Solve: 9x-7≤28+4x;x€W

Natasha_Volkova [10]

Answer:

z ≤ 7

Step-by-step explanation:

9x - 7 ≤ 28 + 4x

9x - 4x ≤ 28 + 7

5x ≤ 35

x ≤ 35 / 5

x ≤ 7

4 0

3 years ago

Read 2 more answers

Which equation describes the sum of the vectors plotted below?

Alex787 [66]

Answer: $A) \ 3\vec{x} -2\vec{y}$

Step-by-step explanation:

The resultant can be calculated using triangular law of vector addition as :

$\rm \vec{r}=\vec{AB} +\vec{AC}=2x+y+x-3y=\boxed{3x-2y }$

8 0

3 years ago

If you were opening a savings account with compound interest, would you prefer an account that offers annual compounding, quarte

oksian1 [2.3K]

Daily compounding, you can gain more interest this way.

8 0

3 years ago

A tank contains 90 kg of salt and 1000 L of water. A solution of a concentration 0.045 kg of salt per liter enters a tank at the

Andreyy89

Answer:

Step-by-step explanation:

concentration = amount of salt/solution

A) Initial concentration= 90/1000 = 0.09

Q = quantity of salt

Q(0) = 90 kg

Inflow rate = 8 l/min

Outflow rate = 8 l/min

Solution = 1000 L at any time t.

Salt inflow = 0.045 * 8 per minute

= 0.36 kg per minute

This is mixed and drains from the tank.

Outflow = $\frac{Q(t)}{1000}$

Thus rate of change of salt

Q'(t) = inflow - outflow = $0.36-\frac{Q(t)}{1000} \\=\frac{360-Q(t)}{1000}$

Separate the variables and integrate

$\frac{1000dQ}{360-q(t)} =dt\\-1000 ln |360-Q(t)| = t+C\\ln |360-Q(t)| = -0.001+C'\\360-Q(t) = Ae^{-0.001t} \\Q(t) = 360-Ae^{-0.001t}$

Use the fact that Q(0) = 90

90 = 360-A

A = 270

So

$Q(t) = 360-270e^{-0.001t}$

B) Q(t) = 360-270e^-0.004 = 91.07784

C) When t approaches infinity, we get

Q(t) tends to 360

So concentration =360/1000 = 0.36

8 0

3 years ago