All categories

3 years ago

–28 = 2f – 44 f = [?]

Mathematics

2 answers:

pishuonlain [190]3 years ago

7 0

-28=2f-44

-28+44=2f

16=2f

f=16÷2

f=8

joja [24]3 years ago

5 0

-28= 2f - 44
-28+44= 16
16/2=8
-28= 2•8 - 44

You might be interested in

Evaluate 5x² – 3x+2 for x = -3, A. -52 B. 28 C. 38 D. 56

hoa [83]

Answer:

Step-by-step explanation:

We just plugin -3 for all the x values. We get: 5(-3)^2+-3(-3)+2.

(-3)^2=9, -3(-3)= 9 because it is the same as (-3)^2.

We get 5(9)+9+2=>45+11=>56=>D.

And no, that was not meant be an emoji.

7 0

4 years ago

Read 2 more answers

5 + 6 - (-3) - 8 + 4 -3

Komok [63]

Okay, so -

We have one very important thing here. This little part 6 - (-3). 

Now, it's essential to remember that when we have two negatives like this, we simply draw a line straight down. It becomes a positive!

So, our question is essentially 5 + 6 + 3 - 8 + 4 - 3 = ? instead of 5 + 6 - (-3) - 8 + 4 - 3! =)

With that in mind, we simply solve left to right.

11 + 3 - 8 + 4 - 3 = ?

14 - 8 + 4 - 3 = ?

6 + 4 - 3 = ?

10 - 3 = ?

7 is our final answer! =)

6 0

3 years ago

Samuel used 1/5 of an ounce of butter to make 1/25 of pound of jelly how many ounces of butter is there per pound of jelly

Svetach [21]

1 ounce --> ?
1/5 --> 1/25
i chaged the freactions to decimal this is what i got,
1ounce --> ?
0.2 ounce--> 0.04 ounces
divide 0.2 ounces by 0.04 ounces and you'll get the answer
0.2 is the answer per pound of jelly you will use o.2 ounces

4 0

3 years ago

What is 3 times 4 minus 3 times 6 minus 2

Vera_Pavlovna [14]

Answer:

The answer is - 8

Step-by-step explanation:

You do the multiplication first then the subtraction

6 0

3 years ago

Read 2 more answers

Three microcontrollers are needed to operate a specific type of robot. Such a robot stops working whenever one or more microcont

Xelga [282]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

(a)

The robot will work only if all the micro controller works on the competition day.

The probability of the micro controller's failing is $\frac{1}{2}$ .

The probability of the micro controller's success is $\frac{1}{2}$ .

Hence, the required probability is $\frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} = \frac{1}{8}$ .

(b)

From the three micro controller, one can be chosen in $^3C_1 = 3$ ways.

The probability here is $\frac{1}{2} \times \frac{1}{2} \times \frac{1}{2}\times3 = \frac{3}{8}$ .

(c)

If from the four micro controllers, one fails, then also they can manage to make the robot work.

From the 4, 1 can be chosen in 4 ways.

This one can either work properly or not.

If it works properly, then the probability of other 3 will work properly is $(\frac{1}{2} )^4 = \frac{1}{16}$ .

If the chosen one does not work properly, then the probability of other 3 will work properly is $(\frac{1}{2} )^4 = \frac{1}{16}$ .

The required probability is $3(\frac{1}{16} + \frac{1}{16} ) = \frac{3}{8}$ .

(d)

In this case there are total 6 micro controllers.

From these 6 controllers, 3 can be chosen as $^6C_3 = \frac{6!}{3!\times3!} = 20$ ways.

The probability that the team is able to reshuffle the micro controllers to make one robot work is $20\times(\frac{1}{2} )^6 = \frac{5}{16}$ .

3 0

4 years ago