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hoa [83]
3 years ago
14

Describe how to transform (^6 sqrt x^5)^7 into an expression with a rational exponent.

Mathematics
1 answer:
solniwko [45]3 years ago
5 0
\bf a^{\frac{{ n}}{{ m}}} \implies  \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}\\\\
-------------------------------\\\\
\left(\sqrt[6]{x^5}\right)^7\implies \left( x^{\frac{5}{6}} \right)^7\implies x^{\frac{5}{6}\cdot 7} \implies x^{\frac{5\cdot 7}{6}}\implies x^{\frac{35}{6}}
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Answer:

a) P(R

And we can find this probability using the normal standard table or excel and we got:

P(z

b) P(R>110)=P(\frac{R-\mu}{\sigma}>\frac{110-\mu}{\sigma})=P(Z>\frac{110-100}{3.606})=P(Z>2.774)

And we can find this probability using the complement rule and the normal standard table or excel and we got:

P(z>2.774)=1-P(Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the time for the step 1 and Y the time for the step 2, we define the random variable R= X+Y for the total time and the distribution for R assuming independence between X and Y is:

R \sim N(40+60 = 100,\sqrt{2^2 +3^2}= 3.606 s)  

Where \mu=65.5 and \sigma=2.6

We are interested on this probability

P(R

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{R-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(R

And we can find this probability using the normal standard table or excel and we got:

P(z

Part b

P(R>110)=P(\frac{R-\mu}{\sigma}>\frac{110-\mu}{\sigma})=P(Z>\frac{110-100}{3.606})=P(Z>2.774)

And we can find this probability using the complement rule and the normal standard table or excel and we got:

P(z>2.774)=1-P(Z

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