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Dmitry [639]
2 years ago
10

3 consecutive multiples of 7 are 777

Mathematics
2 answers:
jasenka [17]2 years ago
4 0

Answer:

252, 259 and 266

Step-by-step explanation:

Multiples of a number are those numbers that are divisible by that. Like if x and y are any two numbers then if y is a multiple of x then the remainder should be equal to zero when x is divided from y.

Y_Kistochka [10]2 years ago
3 0

Answer:

Three consecutive multiples of 7 whose sum is equal to 777 are 252, 259 and 266.

<em>Please click above answer.</em>

Please do 3 brainliests because I need.

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Six different​ second-year medical students at Bellevue Hospital measured the blood pressure of the same person. The systolic re
Yanka [14]

Answer:

Range=14

\sigma^2 =32.4

\sigma = 5 .7

The standard deviation will remain unchanged.

Step-by-step explanation:

Given

Data: 136, 129, 141, 139, 138, 127

Solving (a): The range

This is calculated as:

Range = Highest - Least

Where:

Highest = 141; Least = 127

So:

Range=141-127

Range=14

Solving (b): The variance

First, we calculate the mean

\bar x = \frac{1}{n} \sum x

\bar x = \frac{1}{6} (136+ 129+ 141+ 139+ 138+ 127)

\bar x = \frac{1}{6} *810

\bar x = 135

The variance is calculated as:

\sigma^2 =\frac{1}{n-1}\sum(x - \bar x)^2

So, we have:

\sigma^2 =\frac{1}{6-1}*[(136 - 135)^2 +(129 - 135)^2 +(141 - 135)^2 +(139 - 135)^2 +(138 - 135)^2 +(127 - 135)^2]

\sigma^2 =\frac{1}{5}*[162]

\sigma^2 =32.4

Solving (c): The standard deviation

This is calculated as:

\sigma = \sqrt {\sigma^2 }

\sigma = \sqrt {32.4}

\sigma = 5 .7 --- approximately

Solving (d): With the stated condition, the standard deviation will remain unchanged.

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Answer:

a = 9b

divide each side by 9

\frac{a}{9} = b

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Answer:

Some integers are irrational

Step-by-step explanation:

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3 years ago
3 times the measure of an angle is 14 less than the measure of its complement. What is the measure of the angle?
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Let the measure of the angle be x and from that the measure of its complement is 90 - x. The equation that best represent the given condition above is,
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