A. During aerobic respiration, cells take in O2 (Oxygen is an input of cellular respiration) and release CO2, H2O and ATP.
Cellular respiration equation (THIS IS VERY USEFUL :) ):
C6H12O6 (Glucose) + O2 (Oxygen) = 6CO2 (Carbon dioxide) + 6H2O (water) + 36-38 ATP (energy)
NOTE: Inputs are the things going in, outputs are the things being produced.
WHY THE OTHER ANSWERS ARE WRONG:
B. Not B because it mentions the process of fermentation which is anaerobic.
C. Not C because insulin has nothing to do with cellular respiration in particular but rather blood glucose level homeostasis
D. Not D because although it is partially 'correct', the actual wording (inhaled /exhaled) is incorrect as H2O is produced not exhaled. ATP energy is also produced.
I love art so you should get some holograghic paper for the title and for the system get clay or some sponge so the organs can pop out off the board and on the sides of the board put like the organ puffed up on the sides and the definito=ions or whatever under them.
Answer:
The answer is prokaryotes
The answer is <span>The q allele will go up.
Let's assume that the population is in the Hardy-Weinberg equilibrium and there are only two alleles of some gene. </span>The Hardy-Weinberg principle can be expressed as p + q = 1 where p is the frequency of the p allele and q the frequency of q allele.
Let initial frequencies be:
p = 0.6
q = 0.4
p + q = 1
0.6 + 0.4 = 1
Now, after the environmental change, the frequency of the p allele has gone down, for example p = 0.3
So, p goes from 0.6 to 0.3.
The frequency of the q allele can be calculate using Hardy-Weinberg principle:
p + q = 1
q = 1 - p
q = 1 - 0.3
q = 0.7
Thus, q goes from 0.4 to 0.7.
