3.24a khbbddhufbvbncyhncfnfghvvxdggnhk
Answer:
1/8
Explanation:
Given that the trihybrid parents have AaBbCc genotype for fruit color. The trait is a quantitative trait i.e. each dominant allele will have an additive effect on it. In this case, AaBbCc and AABBCC will not produce same fruit color because AaBbCc has only three loci contributing to the color while in AABBCC all the six loci are contributing to the color. For an offspring to be exactly similar to the AaBbCc parents it should have the same genotype of AaBbCc.
The probability of Aa to come from a cross between Aa and Aa is 2/4 or 1/2
The probability of Bb to come from a cross between Bb and Bb is 2/4 or 1/2
The probability of Cc to come from a cross between Cc and Cc is 2/4 or 1/2
So the collective probability of AaBbCc offspring from a cross between AaBbCc and AaBbCc parents would be=
1/2 * 1/2 * 1/2 = 1/8
Hence, assuming no effects of the environment, 1/8 of the offspring will have the same fruit color phenotype as the trihybrid parent.
Answer:
what re the options for each?
Explanation:
Carpet, meta carpel and phalanges
Answer:
If a DNA strand has the base sequence TTCCGGAA the complementary strand has the sequence AAGGCCTT.
Explanation:
A DNA molecule is constructed from sequences of its four nitrogenous bases: adenine, thymine, guanine and cytosine. Since DNA is made up of two strands, the sequence of nitrogenous bases of one strand is complementary to the other
.
The complementarity of the bases is a characteristic of the nitrogenous bases in the nucleic acids to combine with their complementary base, which is the same as saying that purines complement with pyramidines.
- <em>Adenine is combined with Thymine A=T
</em>
- <em>Cytosine is complemented with Guanina C≡G
</em>
In this way, given a sequence on a DNA strand
:
<em> T-T-C-C-G-G-A-A</em>
The complementary strand will have this sequence:
<em> A-A-G-G-C-C-T-T</em>