The complete square starting with $x^2+14x$ would be $x^2+14x+49$ , since the square would be $(x+7)^2$ . To make this square perfect, then, you would need to add 46 to make 49 with the 3. Hope this helps!

6 0

3 years ago

Read 2 more answers

What is the answer to this question please help

LuckyWell [14K]

Answer:

(x+5)(x-3)

Step-by-step explanation:

We can factor the equation to be

(x+5)(x-3)

5 0

3 years ago

BRAINLIEST IF YOU HELP the correct simplification of 7x2(6x + 3x2 − 4)? A 21x4 − 42x3 + 28x2 B 42x4 + 21x3 − 3x2 C 21x4 + 42x3 −

exis [7]

$\text{Simplify:}\\\\7x^2(6x + 3x^2- 4)\\\\\text{Use the distributive property:}\\\\42x^3+21x^4-28x^2\\\\\text{You can arrange them by exponent}\\\\21x^4+42x^3-28x^2\\\\\text{This means that your answer will be C).} 21x^4 + 42x^3 - 28x^2\\\\\boxed{\text{C).}\,\,21x^4 + 42x^3 - 28x^2}$

3 0

3 years ago