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3 years ago

How do you do this question?

Mathematics

1 answer:

KonstantinChe [14]3 years ago

4 0

Answer:

A. 2 < t < 4

Step-by-step explanation:

The position of the particle is given to be:

y = t³ − 6t² + 9t

The velocity of the particle is:

dy/dt = 3t² − 12t + 9

The acceleration of the particle is:

d²y/dt² = 6t − 12

Find when the acceleration is 0:

0 = 6t − 12

t = 2

In the interval 0 < t < 2, the acceleration is negative (the particle's velocity is decreasing).

In the interval 2 < t < 4, the acceleration is positive (the particle's velocity is increasing).

You might be interested in

Which point lies on the circle represented by the equation (x+5) + (y-9) = 8

olga_2 [115]

Answer:

(-5,9+√8)

Step-by-step explanation:

There are two ways in which you can find a point that lies in the circle. One of them is to do y the subject of the formula, and another one is to determine the center of the circumference, and with the information of the radius, you can sum this value upward or downward.

the general equation of a circle is:

$(x-h)^2+(y-k)^2=r^2$

with center at (h,k)

you have the following equation:

$(x+5)^2+(y-9)^2=8\\\\h=-5\\\\k=9\\\\r=\sqrt{8}$

Then, the center is (-5,9)

if you sum the value of the radius in one of the fourth directions (up, down, left, right), for example upward you have

$(-5,9+r)=(-5,9+\sqrt{8})$

Then, one point that lies in the circle is (-5,9+√8)

3 0

3 years ago

Plzz help and explain

Mumz [18]

The height is 5 and 1/4 then the base is 2 and 1/2

You can convert these fractions into decimals and them multiply them to get your area.

6 0

3 years ago

(8-5/2-2)-4 =? Please helping me!!!

frez [133]

Answer: Hope This Helps!

Step-by-step explanation:

Simplify the expression.

Exact Form:

87/40

Decimal Form:

2.175

Mixed Number Form:

2 7/40

5 0

2 years ago

The graph of h(x) is shown. Graph of h of x that begins in quadrant two and decreases rapidly following the vertical line which

fgiga [73]

Answer:

x-intercept

The point at which the curve crosses the x-axis, so when y = 0.

From inspection of the graph, the curve appears to cross the x-axis when x = -4, so the x-intercept is (-4, 0)

y-intercept

The point at which the curve crosses the y-axis, so when x = 0.

From inspection of the graph, the curve appears to cross the y-axis when y = -1, so the y-intercept is (0, -1)

Asymptote

A line which the curve gets infinitely close to, but never touches.

From inspection of the graph, the curve appears to get infinitely close to but never touches the vertical line at x = -5, so the vertical asymptote is x = -5

(Please note: we cannot be sure that there is a horizontal asymptote at y = -2 without knowing the equation of the graph, or seeing a larger portion of the graph).

5 0

2 years ago

Read 2 more answers

What is 874 base 9 multiplied by 676 base 9?

Gekata [30.6K]

Consider the digit expansion of one of the numbers, say,

676₉ = 600₉ + 70₉ + 6₉

then distribute 874₉ over this sum.

874₉ • 6₉ = (8•6)(7•6)(4•6)₉ = (48)(42)(24)₉

• 48 = 45 + 3 = 5•9¹ + 3•9⁰ = 53₉

• 42 = 36 + 6 = 4•9¹ + 6•9⁰ = 46₉

• 24 = 18 + 6 = 2•9¹ + 6•9⁰ = 26₉

874₉ • 6₉ = 5(3 + 4)(6 + 2)6₉ = 5786₉

874₉ • 70₉ = (8•7)(7•7)(4•7)0₉ = (56)(49)(28)0₉

• 56 = 54 + 2 = 6•9¹ + 2•9⁰ = 62₉

• 49 = 45 + 4 = 5•9¹ + 4•9⁰ = 54₉

• 28 = 27 + 1 = 3•9¹ + 1•9⁰ = 31₉

874₉ • 70₉ = 6(2 + 5)(4 + 3)10₉ = 67710₉

874₉ • 600₉ = (874•6)00₉ = 578600₉

Then

874₉ • 676₉ = 578600₉ + 67710₉ + 5786₉

= 5(7 + 6)(8 + 7 + 5)(6 + 7 + 7)(0 + 1 + 8)(0 + 0 + 6)₉

= 5(13)(20)(20)(1•9)6₉

= 5(13)(20)(20 + 1)06₉

= 5(13)(20)(2•9 + 3)06₉

= 5(13)(20 + 2)306₉

= 5(13)(2•9 + 4)306₉

= 5(13 + 2)4306₉

= 5(1•9 + 6)4306₉

= (5 + 1)64306₉

= 664306₉

4 0

3 years ago