ve%20%5C%3A%20for%20%5C%3A%20p" id="TexFormula1" title="if \: 100 { \: }^{2} \: = 251p \: solve \: for \: p" alt="if \: 100 { \: }^{2} \: = 251p \: solve \: for \: p" align="absmiddle" class="latex-formula">
2 answers:
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Answer:
1. 144 2. 16 3. 1 4. 3x-6
Step-by-step explanation:
So think of this as a function in a function. So you work from the inside to the outside. So for problem 1, we start with f(4)) [you read it "f of 4"] so what is the solution when x = 4, since f(x) means the function of x so f(4) means 'the function of 4' inside f(x).
Since f(x) = 3x then f(4) = 3(4) [notice how you substitute the 4 everywhere you see a letter x]
so f(4) = 12, now you work the next part h(f(4)) since f(4)=12 then h(12)
So take the h(x) function which is h(x) = then h(12) =
so h(12) = 144