All categories

2 years ago

PLEASE HELP DUE IN 5 MINUTES!! NO LINKS! HELP WITH THE FIRST ONE ONLY!

Mathematics

1 answer:

PSYCHO15rus [73]2 years ago

4 0

Answer:

PR=130, MPR=180, MRT=180, MT=130 HOPE THIS HELPED

Step-by-step explanation:

You might be interested in

FYI, I don't have many points.

zimovet [89]

Answer:

ok i see that question it would be 3

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

How to factor a trinomial x^2+11x+19

Tresset [83]

Answer:

this trinomial is prime, and cannot be factored.

Step-by-step explanation:

when expanding the equation, you multiply the last term by the first term's coefficient, and then find two factors that multiply to that product, and sum to the middle coefficient.

1 * 19 = 19

there are no factors that will multiply to 19 and sum to 11. thus, this polynomial is prime.

4 0

3 years ago

What is the difference between constructing a square and constructing a regular hexagon?

dexar [7]

Answer:

The diameter of the circle is used for the square construction, but the radius of the circle is used for the regular hexagon construction.Step-by-step explanation:

5 0

2 years ago

9(14-5)-42 evaluate expression

Ulleksa [173]

Good evening

Answer:

Step-by-step explanation:

9(14-5)-42 = 9×9 - 42

= 81 - 42

= 39

________________

8 0

3 years ago

Is anybody else here to help me ??

Akimi4 [234]

Answer:

$\cot(x)+\cot(\frac{\pi}{2}-x)$

$\cot(x)+\tan(x)$

$\frac{\cos(x)}{\sin(x)}+\frac{\sin(x)}{\cos(x)}$

$\frac{1}{\sin(x)}(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})$

$\csc(x)(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})$

$\csc(x)[\frac{\cos(x)\cos(x)}{\cos(x)}+\sin(x)\frac{sin(x)}{\cos(x)}]$

$\csc(x)[\frac{\cos(x)\cos(x)+\sin(x)\sin(x)}{\cos(x)}]$

$\csc(x)[\frac{\cos^2(x)+\sin^2(x)}{\cos(x)}]$

$\csc(x)[\frac{1}{\cos(x)}]$

$\csc(x)[\sec(x)]$

$\csc(x)[\csc(\frac{\pi}{2}-x)]$

$\csc(x)\csc(\frac{\pi}{2}-x)$

Step-by-step explanation:

I'm going to use $x$ instead of $\theta$ because it is less characters for me to type.

I'm going to start with the left hand side and see if I can turn it into the right hand side.

$\cot(x)+\cot(\frac{\pi}{2}-x)$

I'm going to use a cofunction identity for the 2nd term.

This is the identity: $\tan(x)=\cot(\frac{\pi}{2}-x)$ I'm going to use there.

$\cot(x)+\tan(x)$

I'm going to rewrite this in terms of $\sin(x)$ and $\cos(x)$ because I prefer to work in those terms. My objective here is to some how write this sum as a product.