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steposvetlana [31]
3 years ago
7

PLEASE HELP DUE IN 5 MINUTES!! NO LINKS! HELP WITH THE FIRST ONE ONLY!

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
4 0

Answer:

PR=130, MPR=180, MRT=180, MT=130 HOPE THIS HELPED

Step-by-step explanation:

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Please help <br> -HA<br> -LL<br> -HL<br> -LA
yulyashka [42]

Answer:

Ha

Step-by-step explanation:

7 0
3 years ago
How do you do this question?
OLEGan [10]

Step-by-step explanation:

∫ dt / (cos²(t) ⁹√(1 + tan(t)))

If u = 1 + tan(t), then du = sec²(t) dt.

∫ du / ⁹√u

∫ u^(-1/9) du

9/8 u^(8/9) + C

9/8 (1 + tan(t))^(8/9) + C

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4 years ago
In the adjoining figure, ABCD is a square of side 28 cm find the area of shaded region​
vodka [1.7K]

Step-by-step explanation:

Area of square

A = s²

A = 28²

A = 28 × 28

A = 784 cm²

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3 years ago
HELP PLEASEE<br> What is the range of the graph below?
Grace [21]

Answer:

d

Step-by-step explanation:

range is how far the graph goes from bottom to top.

7 0
3 years ago
Read 2 more answers
15x^2 + 41x + 28 <br><br>STEP BY STEP ANSWER PLSSS​
maria [59]

Answer:

(3x+4)(5x+7)

Step-by-step explanation:

15x^2 +41x+28

Factor the expression by grouping. First, the expression needs to be rewritten as 15x^2 +ax+bx+28. To find a and b, set up a system to be solved.

a+b=41

ab=15×28=420

Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 420.

1,420

2,210

3,140

4,105

5,84

6,70

7,60

10,42

12,35

14,30

15,28

20,21

Calculate the sum for each pair.

1+420=421

2+210=212

3+140=143

4+105=109

5+84=89

6+70=76

7+60=67

10+42=52

12+35=47

14+30=44

15+28=43

20+21=41

The solution is the pair that gives sum 41.

a=20

b=21

Rewrite 15x^2 +41x+28 as (15x^2 +20x)+(21x+28).

(15x^2 +20x)+(21x+28)

Factor out 5x in the first and 7 in the second group.

5x(3x+4)+7(3x+4)

Factor out common term 3x+4 by using distributive property.

(3x+4)(5x+7)

7 0
3 years ago
Read 2 more answers
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