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steposvetlana [31]
2 years ago
7

PLEASE HELP DUE IN 5 MINUTES!! NO LINKS! HELP WITH THE FIRST ONE ONLY!

Mathematics
1 answer:
PSYCHO15rus [73]2 years ago
4 0

Answer:

PR=130, MPR=180, MRT=180, MT=130 HOPE THIS HELPED

Step-by-step explanation:

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What additional information do you need to prove triangle ABC ~ triangle JKL
irga5000 [103]

Answer:

no additional information will help because the triangles are not similar

Step-by-step explanation:

Similar triangles have 3 pairs of congruent, corresponding angles.

Let's look at triangle ABC. Two angle measures are given: 51 deg and 63 deg.

180 - 51 - 63 - 66

The measure of the thrid angle is 66 deg.

One anlgle measure of triangle JKL is given. It is 66 deg.

Since <J is not congruent to any angle of triangler ABC, the triangles are not similar.

Answer: no additional information will help because the triangles are not similar

4 0
3 years ago
What is the absolute value transformation of this function?
xxMikexx [17]

Answer:

k(x) = -|x + 2| + 3

Step-by-step explanation:

Parent function of the absolute function given in the graph,

f(x) = |x|

1). Function 'g' is reflected across the x-axis, then the image will be,

  h(x) = -f(x) = -|x|

2). Function 'h' the shifted 2 units left and 3 units upwards, image function will be,

  k(x) = h(x + 2) + 3

  k(x) = -|x + 2| + 3

Therefore, the transformed function is k(x) = -|x + 2| + 3.

6 0
2 years ago
Find the value of pq - r/4 when p= -8 and q= -3 and r= 68
andrey2020 [161]

Answer:

7

Step-by-step explanation:

pq - r/4

(-8)(-3) - 68/4

-8 x -3 = 24 (2 negatives equal a positive)

24 - 68/4

68/4 = 17

24-17 = 7

6 0
3 years ago
10 points
ahrayia [7]

Answer:

To find the difference between two numbers, subtract the number with the smallest value from the number with the largest value. The product of this sum is the difference between the two numbers.

4 0
2 years ago
Read 2 more answers
Autum school holding a voleturing challeng. Students are encouraged to volunteer for at least 1 1/2 hours per week. Volenteers a
Pani-rosa [81]

Given :

Challenge given is to volunteer for about 1 1/2 hours per week .

Autum did at a rate of 6 3/4 hours per week .

To Find :

The comparison ( ratio )  her volunteers rate with the challenge rate .

Solution :

Simplifying challenge rate in in normal fraction , 1\dfrac{1}{2}=\dfrac{2+1}{2}=\dfrac{3}{2} .

Also , simplifying her rate , 6\dfrac{3}{4}=\dfrac{(6\times 4)+3}{4}=\dfrac{27}{4} .

Now , ratio of his work by challenge is :

R=\dfrac{\dfrac{27}{4}}{\dfrac{3}{2}}\\\\\\R=\dfrac{27\times 2}{4\times 3}\\\\R=\dfrac{9}{2}

Therefore , the ratio is 9/2 or 4 1/2 .

Hence , this is the required solution .

8 0
3 years ago
Read 2 more answers
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