Answer: the remaining credit after 79 minutes of call is $15.52
Step-by-step explanation:
let x represent the number of minutes of call.
Let y represent the remaining credit after x minutes of call.
If we plot y on the vertical axis and x on the horizontal axis, a straight line would be formed. The slope of the straight line would be
Slope, m = (17.2 - 19.84)/(65 - 43)
m = - 2.64/22 = - 0.12
The equation of the straight line can be represented in the slope-intercept form, y = mx + c
Where
c = intercept
m = slope
To determine the intercept, we would substitute x = 65, y = 17.2 and m = - 0.12 into y = mx + c. It becomes
17.2 = - 0.12 × 65 + c
17.2 = - 7.8 + c
c = 17.2 + 7.8
c = 25
The linear function becomes
y = - 0.12x + 25
Therefore, the remaining credit after 79 minutes of call is
y = - 0.12 × 79 + 25
y = - 9.4 + 25
y = 15.52
Answer:
81
Step-by-step explanation:
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Answer:
The answer is 165/6, or 27 and one half.
Step-by-step explanation:
Answer:

Step-by-step explanation:
By definition,
and
. Since since
is negative,
must also be negative, and since
is positive, we must be in Quadrant II.
In a right triangle, the sine of an angle is equal to its opposite side divided by the hypotenuse. The cosine of an angle in a right triangle is equal to its adjacent side divided by the hypotenuse. Therefore, we can draw a right triangle in Quadrant II, where the opposite side to angle theta is 8 and the hypotenuse of the triangle is 17.
To find the remaining leg, use to the Pythagorean Theorem, where
, where
is the hypotenuse, or longest side, of the right triangle and
and
are the two legs of the right triangle.
Solving, we get:

Since all values of cosine theta are negative in Quadrant II, all values of secant theta must also be negative in Quadrant II.
Thus, we have:

Answer:
Area = y² + 2x + 1
Step-by-step explanation:
You have to combine like terms:
The little square is 1 unit, so 1
The two bars are each worth x, so 2 * x = 2x
The big square is y²
The total area is the sum of all terms:
Area = y² + 2x + 1
-Chetan K