PLZ HELP

The credit remaining on a phone card (in dollars) is a linear function of the total calling time made with the card (in minutes)

Ivan

Answer: the remaining credit after 79 minutes of call is $15.52

Step-by-step explanation:

let x represent the number of minutes of call.

Let y represent the remaining credit after x minutes of call.

If we plot y on the vertical axis and x on the horizontal axis, a straight line would be formed. The slope of the straight line would be

Slope, m = (17.2 - 19.84)/(65 - 43)

m = - 2.64/22 = - 0.12

The equation of the straight line can be represented in the slope-intercept form, y = mx + c

Where

c = intercept

m = slope

To determine the intercept, we would substitute x = 65, y = 17.2 and m = - 0.12 into y = mx + c. It becomes

17.2 = - 0.12 × 65 + c

17.2 = - 7.8 + c

c = 17.2 + 7.8

c = 25

The linear function becomes

y = - 0.12x + 25

Therefore, the remaining credit after 79 minutes of call is

y = - 0.12 × 79 + 25

y = - 9.4 + 25

y = 15.52

6 0

3 years ago

Evaluate the expression for x=5, y=-3 and z=7<br> (x2 – z) (22+5)

Contact [7]

Answer:

81

Step-by-step explanation:

Hello! Thanks for letting me answer your question! If you have any more questions feel free to ask me! If not, Have a WONDERFUL day and Please don't forget to consider making me Brainliest on your question today!

7 0

4 years ago

ben has 165 pictures he puts 6 pictures on each page of a photo album. how many pages of the album did ben fill? how many pages

ladessa [460]

Answer:

The answer is 165/6, or 27 and one half.

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

If sin theta = 8/17 and cot theta < 0, what is sec theta?

klasskru [66]

Answer:

$-\frac{17}{15}$

Step-by-step explanation:

By definition, $\cot \theta=\frac{1}{\tan \theta}$ and $\sec \theta=\frac{1}{\cos \theta}$ . Since since $\cot \theta$ is negative, $\tan \theta$ must also be negative, and since $\sin \theta$ is positive, we must be in Quadrant II.

In a right triangle, the sine of an angle is equal to its opposite side divided by the hypotenuse. The cosine of an angle in a right triangle is equal to its adjacent side divided by the hypotenuse. Therefore, we can draw a right triangle in Quadrant II, where the opposite side to angle theta is 8 and the hypotenuse of the triangle is 17.

To find the remaining leg, use to the Pythagorean Theorem, where $a^2+b^2=c^2$ , where $c$ is the hypotenuse, or longest side, of the right triangle and $a$ and $b$ are the two legs of the right triangle.