The answer is: " 128 oz. " .
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There are: " 128 oz. " (in " 8 lbs." ) .
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Explanation:
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Set up a proportion; as a fraction; as follows:
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400/ 25 = x / 8 ;
in which: "x" = the number of "ounces [oz.] there are in "8 lbs." ;
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We shall solve for "x" , the answer to the problem:
Cross-factor multiply:
25x = (400) * 8 ;
→ 25x = 3200 ;
Divide each side of the equation by "25" ; to isolate "x" on one side of the equation; & to solve for "x" ;
→ 25x / 25 = 3200 / 25 ;
→ x = 128 .
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Answer: " 128 oz. " .
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There are: " 128 oz. " (in " 8 lbs." ) .
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Note of interest: " 16 oz. = 1 lb. " (exact conversion).
So; "8 lbs. <span>= ?</span> oz. " ;
→ " 8 lbs. * (16 oz/ 1 lb) = ( 8 * 16) oz. = 128 oz. ; → which is our answer!
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Answer:
12
Step-by-step explanation:
If the perimeter is 58,
take 17(2) for booth sides.
Which you will get 34.
58-34=24
Now you know that the remainder is the two vertical sides.
24/2=12
BC=12
Answer: 5/18
Step-by-step explanation:
The sample space when two 6- sided dice are rolled is given below:
(+) 1 2 3 4 5 6
1 2 3 4 5 6 7
2 3 4 5 6 7 8
3 4 5 6 7 8 9
4 5 6 7 8 9 10
5 6 7 8 9 10 11
6 7 8 9 10 11 12
The total sample space is 36.
Sum greater than 8 are : {9,10,11,12}
which are 10 in number:
Therefore : the probability that the sum of the two numbers on the dice will be greater than 8 will be :
number of the sum greater than 8 / Total sample space
That is ;
P(sum greater than 8) = 10/36
P(sum greater than 8) = 5/18
Answer:
I think its B
Step-by-step explanation:
A=l√[(w/2)²+h²+w]+w√[(l/2)²+h²]
where
l is base length
w base width
h is height
given that the slant side of our pyramid is 856.1 ft with square base of 145 ft, the height of the pyramid will be found by Pythagorean theorem.
c²=a²+b²
hence:
856.1²=a²+72.5²
a=853.025 ft
The Lateral area is therefore going to be:
A=145√[(145/2)²+856.025²+145]+145√[(145/2)²+856.025²]
A=249,136.0025 ft²