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4 years ago

Consider the line y = 2/3x-4

Mathematics

1 answer:

motikmotik4 years ago

5 0

Answer:

For the parallel line it will still have a slpoe of 2/3

Step-by-step explanation:

as for the perpendicular line it will be double like 4/6 so it can meet it at a 90° angle.

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Ryan played in 3 basketball games. He scored 18 points in the first game and 12 points in the second game. If he scored 42 point

stealth61 [152]

The correct answer for this very hard equation would happen to be 12 because 18+12 happens to equal 30 and 42-30 just so happens to equal 12

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3 years ago

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If JK answered / of the Math questions correctly, how many points did she get in a 50- item test?

Fittoniya [83]

Answer:

JK got 30 answers correct on a 50 item test.

Step-by-step explanation:

It is given that:

Total items on test = T = 50

Fraction of total items that were answered correctly = 3/5

We simply have to multiply the total number of questions by the fraction of correct answers.

So,

The correct answered number of items are:

$= \frac{3}{5} * 50\\=30$

Hence,

JK got 30 answers correct on a 50 item test.

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3 years ago

Marcus hired a car service to drive him to the airport. The bill came to $56.80. He gave the driver a 20% tip. How much money di

aleksandr82 [10.1K]

He gave the driver a tip of $11.36

58.80*0.20 = 11.36

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3 years ago

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Which shuttle service has a greater initial value?

Irina-Kira [14]

Answer: The Quick shuttle has a greater initial value

Step-by-step explanation:

The We-Drive Shuttle has a initial value of $20 and the Quick Shuttle has an inital value of $30

6 0

3 years ago

Using properties of sets show that : a) A ∩ (A’ U B) = A ∩ B b) A ∩ (A U B )’ = Ф

asambeis [7]

Answer:

a) From A ∩ A' = ∅, we have;

A ∩ (A' ∪ B) = A ∩ B

b) From A ∩ (A' ∩ B') = (A ∩ A') ∩ B' and A ∩ A' = ∅, we have;

A ∩ (A ∪ B)' = ∅

Step-by-step explanation:

a) By distributive law of sets, we have;

A ∩ (B ∪ C) = (A ∩ B) ∪ (A ∩ C)

From the complementary law of sets, we have;

A ∩ A' = ∅

Therefore, for A ∩ (A' ∪ B) = A ∩ B, we have

A ∩ (A' ∪ B) = (A ∩ A') ∪ (A ∩ B) (distributive law of sets)

A ∩ A' = ∅ (complementary law of sets)

Therefore;

(A ∩ A') ∪ (A ∩ B) = ∅ ∪ (A ∩ B) = (A ∩ B) (Addition to zero identity property)

∴ A ∩ (A' ∪ B) = A ∩ B

b) By De Morgan's law

(A ∪ B)' = A' ∩ B'

Therefore, A ∩ (A ∪ B)' = A ∩ (A' ∩ B')

By associative law of sets, we have;

A ∩ (A' ∩ B') = (A ∩ A') ∩ B'

A ∩ A' = ∅ (complementary law of sets)

Therefore, (A ∩ A') ∩ B' = ∅ ∩ B' = ∅

Which gives;

A ∩ (A ∪ B)' = ∅.

4 0

3 years ago