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Mademuasel [1]
2 years ago
14

Square cubic route of 125

Mathematics
1 answer:
vekshin12 years ago
7 0
125 = 5 × 5 × 5 <span>if you use 5 three times in a multiplication</span> 
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What are the integers that lie between square root 24 and square root 46
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The only integer is 5
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Determine whether each equation is True or False. In case you find a "False" equation, explain why is False.​
elixir [45]

Answer:

(1) TRUE.

(2) FALSE.

(3) FALSE.

(4) TRUE.

(5) FALSE.

Step-by-step explanation:

(1) \sqrt{32} = 2^{\frac{5}{2} }

2^{\frac{5}{2} } = (\sqrt{2} )^5 = (\sqrt{2} \ \times \ \sqrt{2} \ \times \ \sqrt{2} \ \times \ \sqrt{2} \ \times \ \sqrt{2}) = 4\sqrt{2}\\\\\sqrt{32} = \sqrt{16 \ \times \ 2}\ =  \ \sqrt{16} \ \times \ \sqrt{2} \ = \ 4\sqrt{2}

Thus, the equation is TRUE.

(2) 16^{\frac{3}{8} } = 8^2

16^{\frac{3}{8} } =(2^4)^{\frac{3}{8} } = 2^\frac{3}{2} }= (\sqrt{2} )^3 = (\sqrt{2} \ \times \ \sqrt{2} \ \times \ \sqrt{2}) = 2\sqrt{2} \\\\8^2 = 64

Thus, the equation is FALSE.

(3) 4^{\frac{1}{2} } = \sqrt[4]{64}

4^{\frac{1}{2} }= \sqrt{4} = 2\\\\\sqrt[4]{64}  = (64)^{\frac{1}{4} } = (2^6)^{\frac{1}{4} }= 2^{\frac{6}{4} } = 2^{\frac{3}{2} }=(\sqrt{2} )^3 = (\sqrt{2}  \times \sqrt{2}  \times \sqrt{2} ) = 2\sqrt{2}

Thus, the equation is FALSE.

(4) 2^8 = (\sqrt[3]{16} )^6

2^8 = 256\\\\ (\sqrt[3]{16} )^6 = (16)^{\frac{6}{3} } = (2^4)^{\frac{6}{3} } = (2)^{\frac{24}{3} } = 2^8 = 256

Thus, the equation is TRUE.

(5) (\sqrt{64} )^{\frac{1}{3} } = 8^{\frac{1}{6} }\\\\

8^{\frac{1}{6} } = (2^3)^{\frac{1}{6} } = 2^{\frac{3}{6} } = 2^{\frac{1}{2} } = \sqrt{2} \\\\(\sqrt{64} )^{\frac{1}{3} } = (2^6)^{\frac{1}{3} } = 2^{\frac{6}{3} } = 2^2 = 4

Thus, the equation is FALSE.

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2 years ago
Questions:
My name is Ann [436]

The  solution to the expressions given are;

9 -9t/ 12 - 5t

a. 20/ 169

b. -170/ 169

c.  386/ 169

d.  -10/ 169

<h3>How to solve the expressions</h3>

Given:

\frac{9 - 19t}{12 - 5t}

We can see that both variables in the numerator and denominator have no common factor, thus cannot be factorized further

a. \frac{203}{169} - \frac{183}{169}

First, let's find the lowest common multiple

LCM = 169

= \frac{203 - 183}{169}

= \frac{20}{169}

= 20/ 169

b. \frac{13}{119} - \frac{183}{119}

The lowest common multiple is 119

= \frac{13 - 183}{119}

substract the numerator

= - 170/ 119

c. \frac{203}{169} - \frac{183}{169}

The lowest common multiple is 169

= \frac{203 + 183}{169}

= 386/ 169

d. \frac{9}{169}- \frac{19}{169}

The lowest common multiple is 169

= \frac{9 - 19}{169}

= - 10/ 169

Thus, we have the solutions to be 9 -9t/ 12 - 5t, 20/ 169, -170/ 169, 386/ 169, -10/ 169 respectively.

Learn more about LCM here:

brainly.com/question/12732917

#SPJ1

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1 year ago
Please help me surface area!!
torisob [31]

Answer:

888

Step-by-step explanation:

SA=2xLxW+2xLxH+2xWxH

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